Answer:
Step-by-step explanation:
8w+8 > -10w-5
18w + 8 > -5
18w > -13
w > -13/18
Answer:
40 mph
Step-by-step explanation:
you take your miles 160 and divide them by 4 which is going to be 40
Answer:
10/39
Step-by-step explanation:
The chances of picking a black sock on first try are 8/13, and the chances of picking out a yellow sock without replacing the black sock are 5/12. If you multiply 8/13 and 5/12, you get 40/156, and if you simplify, you will get 10/39 as your answer.
Answer:
The volume of the ball with the drilled hole is:

Step-by-step explanation:
See attached a sketch of the region that is revolved about the y-axis to produce the upper half of the ball. Notice the function y is the equation of a circle centered at the origin with radius 15:

Then we set the integral for the volume by using shell method:

That can be solved by substitution:

The limits of integration also change:
For x=5: 
For x=15: 
So the integral becomes:

If we flip the limits we also get rid of the minus in front, and writing the root as an exponent we get:

Then applying the basic rule we get:

Since that is just half of the solid, we multiply by 2 to get the complete volume:

