Answer:
Step-by-step explanation:
the answer stay the same due to the fact there are no like terms
7w+9+6x
Answer: 1/6
Step-by-step explanation:
A die has 6 numbers which are 1, 2, 3, 4, 5 and 6.
Odd numbers in a die = 1, 3 and 6
Numbers greater than 4 = 5 and 6
Probability of rolling an odd number = 3/6 = 1/2
Probability of rolling a number greater than 4 = 2/6 = 1/3
We then multiply both values gotten. This will be:
= 1/2 × 1/3
= 1/6
Therefore, the probability of rolling an odd number the first time and a number greater than 4 the second time is 1/6.
<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> )
<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> ) × (-1 + <em>i</em> ) / (-1 + <em>i</em> )
<em>z</em> = (3<em>i</em> × (-1 + <em>i</em> )) / ((-1)² - <em>i</em> ²)
<em>z</em> = (-3<em>i</em> + 3<em>i</em> ²) / ((-1)² - <em>i</em> ²)
<em>z</em> = (-3 - 3<em>i </em>) / (1 - (-1))
<em>z</em> = (-3 - 3<em>i </em>) / 2
Note that this number lies in the third quadrant of the complex plane, where both Re(<em>z</em>) and Im(<em>z</em>) are negative. But arctan only returns angles between -<em>π</em>/2 and <em>π</em>/2. So we have
arg(<em>z</em>) = arctan((-3/2)/(-3/2)) - <em>π</em>
arg(<em>z</em>) = arctan(1) - <em>π</em>
arg(<em>z</em>) = <em>π</em>/4 - <em>π</em>
arg(<em>z</em>) = -3<em>π</em>/4
where I'm taking arg(<em>z</em>) to have a range of -<em>π</em> < arg(<em>z</em>) ≤ <em>π</em>.
Answer:
8
Step-by-step explanation:
if we take the 2 that is in the R.H.S and put it in L.H.S
it becomes 16÷2=8
Answer:
4 hours and 45 minutes.
Step-by-step explanation:
Since Christchurch is 2 hours ahead of Sydney, you subtract 2 from 12:45 and get 10:45 so then, you determine the difference between 10:45 and 6:00 AM and it results in 4.75 hours or 4 hours and 45 minutes
