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katovenus [111]
3 years ago
14

I need help guys please help me !

Mathematics
1 answer:
Arisa [49]3 years ago
6 0
S=49p+7*9p=(49+63)p=112P
answer is B
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Answer:

Rotate Figure L 135 degrees counterclockwise around the point of intersection of the arms. Reflect across the right arm

Step-by-step explanation:

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A function is created to represent amount of money spent on lunch if you spent five dollars a day. What restrictions would be ma
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D. the range would include all real numbers.
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3. CDEF is a parallelogram. Find m2C
Nezavi [6.7K]

Answer:

m<C = 56°

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Step-by-step explanation:

Of CDEF is a parallelogram then the sum of angle m<C and angle m<D must be equal to 180°

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The diagram shows a 9cm x 7cm rectangle-based pyramid. all the diagonal sides - TA, TB, TC, AND TD- are length 12cm. M is the mi
lakkis [162]

Answer:

∠TAC is approximately equal to 61.6°

Step-by-step explanation:

The given parameters for the pyramid are;

The dimension for the rectangular base are; Length = 9 cm, width = 7 cm

The length of the diagonal sides, TA, TB, TC, and TD = 12 cm each

The midpoint of the rectangular base = Point M

The diagonal AC = AM + MC

AM = MC as given M is the midpoint of the rectangular base

∴ AC = AM + MC = 2·AM

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AC = √130 cm

∴ AM = AC/2 = (√130)/2 cm

Alternatively, AM = √((9/2 cm)² + (7/2 cm)²) = √(32.5) cm

∠TAC = ∠TAM

By trigonometric ratios, we have;

cos (\theta) = \dfrac{Length \ of \ adjacent \ side \ to \ angle }{Length \ of \ hypotenuse\ side \ to \ angle}

\therefore cos (\angle TAM) = cos (\angle TAC) =  \dfrac{\left (\dfrac{\sqrt{130} }{2}   \right )}{12} = \dfrac{\sqrt{130} }{2 \times 12} = \dfrac{\sqrt{130} }{24}

\angle TAC = arccos \left ( \dfrac{\sqrt{130} }{24} \right ) \approx  61.6 ^{\circ} \ to 1 \ decimal \ place

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2 years ago
Haley’s work evaluating (Negative 2) Superscript 8 is shown below.
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She made a sign error when multiplying and should have had 256 as a final answer.

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