20 • 12 is 240
1/2 • 12 • 4 is 24
so 264
<h2>Answer:</h2><h2>A. 4 13/24</h2><h2 /><h2 /><h2>Hope this helps!!</h2>
If a quadrilateral is a rhombus then:
i) all its sides have equal length,
and
ii) the 2 diagonals are perpendicular and bisect each other.
The 2 diagonals of rhombus JKLM intersect at N.
Then m(MNJ)=90°, |JN|=4 and |NM|=3 units
thus, by the Pythagorean theorem,

The perimeter of the rhombus is 4*5 units=20 units.
Answer: 20 units
The partial product of 4.6×3.5 is 16.1
Subtract 6 which leaves u with -3p=-18 then divide by three on both sides to get p=6