How many 5-digit numbers can be formed using the digits 0, 1, 2, 3, 4, 5, 6, if repetition of digits is not allowed? a. 119 c. 2

Question

3 years ago

5

520 b. 16,807 d. 120 Please select the best answer from the choices provided A B C D

2 answers:

Harman [31] · Answer 1 · 2022-04-14T16:23:46+03:00

Answer: C. 2520

Step-by-step explanation:

Given digits: 0, 1, 2, 3, 4, 5, 6

Total number of digits=7

The number of ways, in which 5-digit numbers can be formed using the above digits if repetition of digits is not allowed is given by permutation:-

$^7P_5=\frac{7!}{(7-5)!}\\\\=\frac{7\times6\times5\times4\times3\times2!}{2!}\\\\=\frac{5040}{2}\\=2520$

Hence, the number of 5 digit numbers can be formed with the given digits (if repetition is not allowed)=2520

Sergio [31] · Answer 2 · 2022-04-14T14:57:22+03:00

3 0

1st digit 1 of 7 numbers

2nd digit 1 of 6 numbers

3rd digit 1 of 5 numbers

4th digit 1 of 4 numbers

5th digit 1 of 3 numbers

7*6*5*4*3 = 2520 combinations