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vodomira [7]
3 years ago
12

5.6e12 in standard form

Mathematics
2 answers:
german3 years ago
5 0
To make 5.6e12 standard you simply move the decimal place right 12 times
5,600,000,000,000
5 Trillion 600 billion
anygoal [31]3 years ago
4 0

The <em><u>correct answer</u></em> is:

5,600,000,000,000 (read "5 trillion, 6 hundred million").

Explanation:

5.6e12 is another way of writing scientific notation.  This is the same as

5.6 x 10^12

The power of 10 tells us how many places to move the decimal.  This means we move it 12 places.  Since the exponent is positive, we are going to make the number larger; this means we move the decimal to the right.  Moving it 12 places gives us

5,600,000,000,000

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Answer:

142 its the ans

Step-by-step explanation:

I'm not sure

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3 years ago
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If there are 52 cards in a deck with four suits (hearts, clubs, diamonds, and spades), how many ways can you select 5 diamonds a
Luba_88 [7]

Answer:

12C5 *(12C3) = 792*220 =174240 ways

Step-by-step explanation:

For this case we know that we have 12 cards of each denomination (hearts, diamonds, clubs and spades) because 12*4= 52

First let's find the number of ways in order to select 5 diamonds. We can use the combinatory formula since the order for this case no matter. The general formula for combinatory is given by:

nCx = \frac{n!}{x! (n-x)!}

So then 12 C5 would be equal to:

12C5 = \frac{12!}{5! (12-5)!}=\frac{12!}{5! 7!} = \frac{12*11*10*9*8*7!}{5! 7!}= \frac{12*11*10*9*8}{5*4*3*2*1}=792

So we have 792 was in order to select 5 diamonds from the total of 12

Now in order to select 3 clubs from the total of 12 we have the following number of ways:

12C3 = \frac{12!}{3! 9!}=\frac{12*11*10*9!}{3! 9!} =\frac{12*11*10}{3*2*1}=220

So then the numbers of ways in order to select 5 diamonds and 3 clubs are:

(12C5)*(12C3) = 792*220 =174240 ways

3 0
3 years ago
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Answer:

27

Step-by-step explanation:

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Answer:

A=1/2(a+b)h

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A=18cm²

3 0
2 years ago
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