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natima [27]
4 years ago
6

What is the solution to log5(10x-1)=log5(9x=7)

Mathematics
1 answer:
zepelin [54]4 years ago
4 0

Domain:\\\\10x-1 > 0\ and\ 9x+7 > 0\\\\10x > 1\ and\ 9x > -7\\\\x > \dfrac{1}{10}\ and\ x > -\dfrac{7}{9}\Rightarrow x > \dfrac{1}{10}\\\\D=\left\{x|x > \dfrac{1}{10}\right\}\\\\\log_5(10x-1)=\log_5(9x+7)\iff10x-1=9x+7\qquad\text{add 1 to both sides}\\\\10x=9x+8\qquad\text{subtract 9x from both sides}\\\\x=8\in D\\\\Answer:\ \boxed{x=8}

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professor190 [17]
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y=2/3y-3


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y=3



2.  -11=2/3x - 3

 -11+3 = 2/3 x   add 3 to both sides to cancel -3

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4 0
4 years ago
For an acute angle 0, the equation sin(0) = cos(6) is true. What is the value of ? Show or explain your answer
weqwewe [10]

Answer:

\theta =84

Step-by-step explanation:

Given

sin(\theta) = cos(6)

Required

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In trigonometry:

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So, we have:

\theta + 6 = 90

Collect Like Terms

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3 years ago
Please help me :) i would appreciate it a lot
Kobotan [32]

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3 years ago
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OleMash [197]

Answer:

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