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natima [27]
4 years ago
6

What is the solution to log5(10x-1)=log5(9x=7)

Mathematics
1 answer:
zepelin [54]4 years ago
4 0

Domain:\\\\10x-1 > 0\ and\ 9x+7 > 0\\\\10x > 1\ and\ 9x > -7\\\\x > \dfrac{1}{10}\ and\ x > -\dfrac{7}{9}\Rightarrow x > \dfrac{1}{10}\\\\D=\left\{x|x > \dfrac{1}{10}\right\}\\\\\log_5(10x-1)=\log_5(9x+7)\iff10x-1=9x+7\qquad\text{add 1 to both sides}\\\\10x=9x+8\qquad\text{subtract 9x from both sides}\\\\x=8\in D\\\\Answer:\ \boxed{x=8}

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Step-by-step explanation:

i hope this helps and i'm sorry if it's wrong have a lovely day

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Which of the following strategies is appropriate for factoring polynomials with 2 terms?
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8 0
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= [ 3 (-0.5) (16) + 3 ] / (-0.5)

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Step-by-step explanation:

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<em>(1 + 2 + 4 + 5 + 8 = 20 ÷ 5 = 4)</em>

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273 ÷ 14 = 19.5

If you don't need to round, 19.5 is correct. However, if you need to round my best guess is 20. Good luck!

7 0
3 years ago
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