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2 years ago

Jillian exercises 5 times a week. She runs 3 miles each morning and bikes in the evening. If she

Mathematics

1 answer:

schepotkina [342]2 years ago

5 0

Answer:

The answer is: " 9 mi. "

Step-by-step explanation:

1 week = 7 days

Total exercise: 30 mi/ wk.

3 mi * 7 = 21 mi. / wk running.

How many miles per week biking?

Assuming that her exercise is strictly: 1) running; and 2) biking:

30 mi - 21 mi. = 9 mi.

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Find the area of the region enclosed by the graphs of the functions

Vaselesa [24]

Answer:

$\displaystyle A = \frac{8}{21}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Terms/Coefficients
Functions
Function Notation
Graphing
Solving systems of equations

Calculus

Area - Integrals

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Addition/Subtraction]: $\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx$

Area of a Region Formula: $\displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx$

Step-by-step explanation:

*Note:

Remember that for the Area of a Region, it is top function minus bottom function.

Step 1: Define

f(x) = x²

g(x) = x⁶

Bounded (Partitioned) by x-axis

Step 2: Identify Bounds of Integration

Find where the functions intersect (x-values) to determine the bounds of integration.

Simply graph the functions to see where the functions intersect (See Graph Attachment).

Interval: [-1, 1]

Lower bound: -1

Upper Bound: 1

Step 3: Find Area of Region

Integration

Substitute in variables [Area of a Region Formula]: $\displaystyle A = \int\limits^1_{-1} {[x^2 - x^6]} \, dx$
[Area] Rewrite [Integration Property - Subtraction]: $\displaystyle A = \int\limits^1_{-1} {x^2} \, dx - \int\limits^1_{-1} {x^6} \, dx$
[Area] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle A = \frac{x^3}{3} \bigg| \limit^1_{-1} - \frac{x^7}{7} \bigg| \limit^1_{-1}$
[Area] Evaluate [Integration Rule - FTC 1]: $\displaystyle A = \frac{2}{3} - \frac{2}{7}$
[Area] Subtract: $\displaystyle A = \frac{8}{21}$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Area Under the Curve - Area of a Region (Integration)

Book: College Calculus 10e

6 0

2 years ago

It takes a hose 2 minutes to fill a rectangular aquarium 8 inches long, 9 inches wide, and 13 inches tall. How long will it take

nirvana33 [79]

To make it easier, you calculate the volume of the first aquarium.

1st aquarium:
V = L x W x H
V = 8 x 9 x 13
V = 72 x 13
V = 936 in.
Rate: 936 in./2 min.

Now that you've got the volume and rate of the first aquarium, you can find how many inches of the aquarium is filled within a minute, which is also known as the unit rate. To do that, you have to divide both the numerator and denominator by their least common multiple, which is 2. 936 divided by 2 is 468 and 2 divided by 2 is 1.
So the unit rate is 468 in./1 min. Now that you've got the unit rate, you can find out how long it'll take to fill the second aquarium up by finding its volume first.

2nd aquarium:
V = L x W x H
V = 21 x 29 x 30
V = 609 x 30
V 18,270 inches

Calculations:
Now, you divide 18,270 by 468 to find how many minutes it will take to fill up the second aquarium. 18,270 divided by 468 is about 39 (the answer wasn't exact, so I said "about").

2nd aquarium's rate:
18,270 in./39 min.

As a result, it'll take about 39 minutes to fill up an aquarium measuring 21 inches by 29 inches by 30 inches using the same hose. I really hope I helped and that you understood my explanation! :) If I didn't, I'm sorry. I tried. :(

7 0

3 years ago

a sandwich shop has 60 stores and 70 percent of the stores are I California. How many stores are in California and Nevada

Aliun [14]

Answer:

The number of stores in California 42

The number of stores in Nevada 18

Step-by-step explanation:

Given as :

The total sandwich shop in California and Nevada = 60

The percentage of shop in California = 70%

So, The percentage of shop in Nevada = 100% - 70% = 30%

Let The number of stores in California = c

And The number of stores in Nevada = n

Now, According to question

The number of stores in California = 70% of the total number of shops

I.e c = $\frac{70}{100}$ × total number of shops

Or, c = $\frac{70}{100}$ × 60

∴ c = $\frac{70\times 60}{100}$

or, c = $\frac{4200}{100}$

or, c = 42

So, The number of stores in California = c =42

Again

The number of stores in Nevada = 30% of the total number of shops

I.e n = $\frac{30}{100}$ × total number of shops

Or, n = $\frac{30}{100}$ × 60

∴ n = $\frac{30\times 60}{100}$

or, n = $\frac{1800}{100}$

or, n = 18

So, The number of stores in Nevada = n = 18

Hence The number of stores in California 42

And The number of stores in Nevada 18 Answer

8 0

3 years ago

Perform the indicated operation. square root of 8 + square root of 50

Dmitrij [34]

Square root of 8 = 2.82842712475

Square root of 50 = 7.07106781187

Sum = 9.89949494

If you would like to round, you can go ahead and round 9.89949494 to 9.9

6 0

3 years ago

Laura bernett is 5 ft-4 inches tall. she stands 12 feet from a streetlight and casts a 9-foot-long shadow. how tall is the stree

xxMikexx [17]

The ratio of the height (h) of the streetlight to its distance to the end of Laura's shadow is the same as the ratio of Laura's height to her distance from the end of her shadow.
.. h/(12+9) = 5'4"/9
.. h = (21/9)*5'4" = 12 4/9 feet
.. h = 12 ft 5 1/3 inches

The streetlight is 12 ft 5 1/3 inches tall.

5 0

3 years ago