I think its B but ima have to check again and get back to you
(-3,5). (2,-3)
x1,y1. x2,y2
y2-y1. -3-5. -8
--------- = ------- = ----- =8 =m
x2-x1. 2-3. -1
plug the rest in
If a secant<span> and a </span><span>tangent of a circle </span><span>are drawn from a point outside the circle, then the product of the lengths of the secant and its external segment equals the square of the length of the tangent segment.
</span><span>
y</span>² = 7(15+7)
<span>y</span>² = 7*22
<span>y</span>² = 154
<span>y = </span>√154
<span>y = 12.4 </span>← to the nearest tenth<span>
</span><span>
</span>
(8*4*2/8*7)^2 x (8^0/7^-3)^3 x 7^-9
Simplify the equations:
(8*4*2/8*7)^2 = (64/56)^2 = (8/7)^2
(8^0/7^-3)^3 = (1/7^-3)^3 = 7^9
Now you have :
(8/7)^2 x 7^9 x 7^-9
Multiply 7^9 x 7^-9 by adding the exponents to get 7^0, which = 1
Now you have:
(8/7)^2 x 1
(8/7)^2 = (8x8) / (7x7) = 64/49
64/49 x 1 = 64/49
