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MAVERICK [17]
3 years ago
11

Help here.... this is question is on factorization of quadratic equations

Mathematics
1 answer:
Marta_Voda [28]3 years ago
5 0
Forgive me if I've read your question wrong but I see
\frac{20-45x^2}{6x^2-x-2}
= \frac{5(4-9x^2)}{6x^2-x-2} =  \frac{5(2-3x)(2+3x)}{6x^2-x-2}
= \frac{5(2-3x)(2+3x)}{(3x+2)(3x-1)} =  \frac{5(2-3x)}{3x-1}
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Two-Step Equations 2/5x−3=−17
Lina20 [59]

Answer:

x =-35

Step-by-step explanation:

2/5x−3=−17

Add 3 to each side

2/5x−3+3=−17+3

2/5x = -14

Multiply each side by 5/2

5/2 * 2/5x = -14 * 5/2

x = -35

3 0
3 years ago
Read 2 more answers
Austin takes 4 hours to make 2 backpacks and a handbag. The time he takes to
lys-0071 [83]

Step-by-step explanation

b = 2h      is given

2 b   + h  = 4 hours     is  given      sub in the top equation

2 (2h) + h = 4

5h = 4

h = 4/5 hr    or  48 minutes

7 0
2 years ago
Given the following two points, find the Rate of Change for the function.<br> (-2,-1) and (4,5)
horsena [70]

Answer:

(6, 6)

Step-by-step explanation:

(x) 4-(-2) = 6

(y) 5-(-1)= 6

5 0
3 years ago
Please help me with this !!!!!!!
Alisiya [41]

Answer:

y = 2x - 1

Step-by-step explanation:

Note the difference between consecutive terms of y are constant, that is

1 - (- 1) = 3 - 1 = 5 - 3 = 7 - 5 = 9 - 7 = 2

Thus the equation is of the form y = 2x ± c ← c is a constant

Substitute values of x to determine the required value of c

x = 0 : 2 × 0 = 0 ← require to subtract 1 for y = - 1

x = 1 : 2 × 1 = 2 ← require to subtract 1 for y = 1

x = 2 : 2 × 2 = 4 ← require to subtract 1 for y = 3, and so on

Thus the required equation is

y = 2x - 1

5 0
3 years ago
What is the equation of the circle with center (16, - 12) and a radius of 5
eimsori [14]

Answer:

x^2+y^2-32x+24y+375=0

Step-by-step explanation:

Equation of circle with given centre (h,k) and radius=r is

(x-h)^2+(y-k)^2=r^2

Given centre are=(16, - 12) and radius= 5

So equation of circle=

(x-16)^2+(y- -12)^2=5^2

x^2-32x+256+y^2+24y+144=25

x^2+y^2-32x+24y+375=0

Answer

5 0
3 years ago
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