The ship sails at 20 km / h.
So
20 km / h x 2 h = 40 km
The boat moves 40 km to the northeast.
Then, in the same way:
20 km / h x 1 h = 20 km.
The ship moves 20 km northwest.
We solve this problem using vectors. In this case, we must perform the sum of two vectors a and b
a) magnitude = 40 km and direction 20 degrees east
b) magnitude = 20 km and direction 10 degrees northwest
In Cartesian coordinates, these vectors are written as:
a) 40sin (20º) i + 40cos (20º) j = 13,68i + 37,59j
b) -20sin (10th) i + 20cos (10th) j = -3,473i + 19,70j
The displacement vector of the ship would be the sum of a + b
a + b = 10,207i + 57,29j Finally, the magnitude of the a + b vector will tell us how far the ship is
√(10.21² + 57.29²) = 58.92km
Answer:
3.04166666667
Step-by-step explanation:
Answer:
x=-2
do your box method and find what multiplies to C and adds to B
to check your answer substitute x with what x=
Answer:
11
Step-by-step explanation:
Replace the values of x and y into the equation.
2(4) + 3 = 8 + 3
= 11
