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3 years ago

Write the equation of the line that passes through (3, –2) and has a slope of 4 in point-slope form.

1 answer:

8 0

The point-slope form is
y - y1 = m(x - x1)

Given (3, -2) and m = 4, so
y - (-2) = 4(x - 3)
y + 2 = 4x - 12
y = 4x - 12 - 2
y = 4x - 14

That is now the line equation.

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mrs_skeptik [129]

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3 years ago

How do you solve this problem?

zimovet [89]

Check the picture below.

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3 years ago

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Quadrilateral CAMP below is a rhombus. The length of PQ is (x + 2) units, and the length of QA is

Phoenix [80]

Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles.

<u>Step-by-step explanation:</u>

As given by the statement in the problem,

Q may be the middle point, which cut the diagonal PA into 2 equal halves.

In rhombus, diagonals meet at right angles.

which means that PQ = QA

x+2 = 3x - 14

Grouping the terms, we will get,

3x -x = 14+ 2

2x = 16

dividing by 2 on both sides, we will get,

x = 16/2 = 8

8+2 = 3(8) - 14 = 10 = PQ or QA

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3 years ago

Find the value of x.

allsm [11]

Answer:

$3 \sqrt{5}$

Step-by-step explanation:

x is the center of the circle.

the chord of length 12 can be splitted into two parts of 6 length each.

since the radius does not change when it touches another end of the circle, we can safely calculate our radius to be the hypotenuse of the triangle formed by the length of the chord and 3.

The explanation is given in the picture

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2 years ago

.) Find – 4.25 +2.5.

Arturiano [62]

The answer is -4 + 2 + -0.25 + 0.5.

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3 years ago