Given:
Distance between two buildings = 
feet apart.
Distance between highway and one building = 
feet.
Distance between highway and second building = 
feet.
To find:
The standard form of the polynomial representing the width of the highway between the two building.
Solution:
We know that,
Width of the highway = Distance between two buildings - Distance of both buildings from highway.
Using the above formula, we get the polynomial for width (W) of the highway.
Combining like terms, we get
Therefore, the width point highway is 
.
Answer:
the angle is changing at a rate of 0.0375 rad/s when the time is t=8 seconds
Step-by-step explanation:
since the line D that starts from the spectator and follows the plane has the following equation
D² = x² + H² , where H= altitude of the plane , x= horizontal distance
then for x=v*t , where v=speed of the plane and t=time since the plane has passed overhead , we have for the elevation angle
tan θ = x/y = v*t /H
θ = tan⁻¹ ( v*t /H)
the rate of change in the angle of the spectator's sight θ with the time is
dθ/dt = 1/1+(v*t /H)² * (v/H) = (v/H)/[1+ (v/H)²*t²]
for t=8 seconds
dθ/dt = (875 ft/s/21000 ft)/[1+ (875 ft/s/21000 ft)²*(8 s)²] = 0.0375 rad/s
therefore the angle is changing at a rate of 0.0375 rad/s when the time is t=8 seconds
I and -2 is the solve for the equation
You get a common denominator. It's 36. Then multiply accordingly to get 16/36-3/36 = 13/36. Hope this helps.
