Question

HELP PLEASEEEEEEEEEeeeee

Answer 1

Might have to experiment a bit to choose the right answer.

In A, the first term is 456 and the common difference is 10.  Each time we have a new term, the next one is the same except that 10 is added.

Suppose n were 1000.  Then we'd have 456 + (1000)(10) = 10456

In B, the first term is 5 and the common ratio is 3.  From 5 we get 15 by mult. 5 by 3.  Similarly, from 135 we get 405 by mult. 135 by 3.  This is a geom. series with first term 5 and common ratio 3.   a_n = a_0*(3)^(n-1).
So if n were to reach 1000, the 1000th term would be 5*3^999, which is a very large number, certainly more than the 10456 you'd reach in A, above.

Can you now examine C and D in the same manner, and then choose the greatest final value?  Safe to continue using n = 1000.