(5/8) / (3/8) =
5/8 * 8/3 =
5/3 =
1 2/3....a = 1, b = 2, c = 3
<u>To find the area of the circle</u>:
⇒ need to know the formula: 
- r: radius or half of diameter's length ⇒ 7 meters
<u>Let's calculate:</u>

<u>The problem asks us to round to the nearest hundreth</u>:

<u>Answer:</u> 
Hope that helps!
Part 1:
Given that the length of the chord is 18 cm and the chord is midway the radius of the circle.
Thus, half the angle formed by the chord at the centre of the circle is given by:

Now,

Therefore, the radius of the circle is
10.4 cm to 1 d.p.
Part 2I:
Given that the radius of the circle is 10 cm and the length of chord AB is 8 cm. Thus, half the length of the chord is 4cm. Let the distance of the mid-point O to /AB/ be x and half the angle formed by the chord at the centre of the circle be θ, then

Now,

Part 2II:
Given that the radius of the circle is 10cm and the angle distended is 80 degrees. Let half the length of chord CD be y, then:

Thus, the length of chord CD = 2(6.428) = 12.856 which is approximately
12.9 cm.
I hope this helps you
length w+5
width w
26=2 (w+5+w)
13=2w+5
2w=8
w=4
length =4+5=9
Answer:
that is step 1 and step 2 and step3
step 4
Let's solve your equation step-by-step.
−4(x+2)=8x+16
Step 1: Simplify both sides of the equation.
−4(x+2)=8x+16
(−4)(x)+(−4)(2)=8x+16(Distribute)
−4x+−8=8x+16
−4x−8=8x+16
Step 2: Subtract 8x from both sides.
−4x−8−8x=8x+16−8x
−12x−8=16
Step 3: Add 8 to both sides.
−12x−8+8=16+8
−12x=24
Step 4: Divide both sides by -12.
−12x
−12
=
24
−12
x=−2
Answer:
x=−2