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Gala2k [10]
3 years ago
7

In a student council executive board election, Aaron and Bonnie are running for president; Clarissa, Devon, and Edward are runni

ng for vice president; and Francine and Gary are running for treasurer. If these are the only candidates, the only offices, and there are no ties, how many different executive boards are possibe?
F. 6
G. 7
H. 12
J. 14
K. 21
Mathematics
1 answer:
goldfiish [28.3K]3 years ago
3 0

Answer: 21


Step-by-step explanation:

there are 7 poeple running total, and 3 election let's just say

take 7*3

that's 21

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Using the order of operations, what is the last calculation that should be done to evaluate
mel-nik [20]

200-(-2) is actually 200-1(-2)

So thats multiplication

Then its 200+2

So addition is the last calculation to be done.

7 0
3 years ago
Read 2 more answers
8*4+32-44+1+1+1+1+1+1
Bas_tet [7]

Answer:

26

Step-by-step explanation:

5 0
3 years ago
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I don’t get this one please HELPPP MEE
iren2701 [21]

Answer:

135

Step-by-step explanation:

The given expression is

\frac{2 {x}^{2} }{x} +x(100 - 15x)

From the question, x=5

So,by substitution,we obtain

=\frac{2({5}^{2})}{5} +5(100 - 15(5))

=\frac{2(25)}{5} +5(100 - 75))

=2(5)+5(25)

= 10+125

= 135

Hence the answer is 135

8 0
3 years ago
I did my best to fit it all lol, can someone please help? <3
pav-90 [236]

Answer:

8a. 0 8b. -1/3

Step-by-step explanation:

slope formula: \frac{y_{2} - y_{1}}{x_{2} - x{1}}

8a. => (8 + 12)/(17 - 17) = 20/0 = 0

8b. (1 + 2)/(-3 - 6) = 3/-9 = - 1/3

3 0
2 years ago
Read 2 more answers
The polynomial function y = x3 -3x2 + 16x - 48 has only one non-repeated x-intercept. What do you know about the complex zeros o
earnstyle [38]
• First way to solve:
We'll manipulate the expression of the equation:

y=x^3-3x^2+16x-48\\\\ y=x^2(x-3)+16(x-3)\\\\ y=(x-3)(x^2+16)

If we have y=0:

x-3=0~~~or~~~x^2+16=0\\\\ x=3~~~or~~~x^2=-16\\\\ x=3~~~or~~~x=\pm\sqrt{-16}\\\\ x=3~~~or~~~x=\pm4i

Then, the function has one real zero (x=3) and two imaginary zeros (4i and -4i).

Answer: B


• Second way to solve:

The degree of the function is 3. So, the function has 3 complex zeros.

Since the coefficients of the function are reals, the imaginary roots are in a even number (a imaginary number and its conjugated)

The function "has only one non-repeated x-intercept", then there is only one real zero.

The number of zeros is 3 and there is 1 real zero. So, there are 2 imaginary zeros.

Answer: B.
3 0
2 years ago
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