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Butoxors [25]
3 years ago
13

The path of a satellite orbiting the earth causes it to pass directly over two tracking stations A and 8, which are 60 mi apart.

When the satellite is on one side of the two stations, the angles of elevation at A and B are measured to be 87.0 degree and 84.2 degree, respectively. (Round your answers to the nearest mile.)
(a) How far is the satellite from station A?
mi
(b) How high is the satellite above the ground?
mi

Mathematics
1 answer:
vesna_86 [32]3 years ago
6 0

Answer:

(a)  2 miles

 (b)  2 miles

Step-by-step explanation:

Let the distance of the satellite from Station A = |AC|

Let the height of the Satellite from the ground = |DC|

(a) Using size rule on triangle ABC, we can find the value of AC with the following relationship:

|AC|/ Sin 84.2 = 10/ Sin 8.8

|AC| = 10 x (Sin 84.2/Sin 8.8)

         =   10 x 0.1529

        =1.529 miles

        = 2 miles (to the nearest mile)

(b) To calculate the |DC|, we apply the relationship of right-angle triangle ADC:

Sin 87 =   |DC|/ 1.529

|DC|   = 1.529 Sin 87

           = 1.526 miles

           = 2 miles (to the nearest mile)

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The area of the region which is inside the polar curve r = 5 sinθ but outside r = 4 will be 3.75 square units.

<h3>What is an area bounded by the curve?</h3>

When the two curves intersect then they bound the region is known as the area bounded by the curve.

The area of the region which is inside the polar curve r = 5 sinθ but outside r = 4 will be

Then the intersection point will be given as

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Then by the integration, we have

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\rightarrow \dfrac{1}{2} [\dfrac{25 \theta }{5} - \dfrac{25 \cos 2\theta }{2} - 16\theta]_{0.927}^{2.214} \\\\\\\rightarrow \dfrac{1}{2} [\dfrac{25(2.214 - 0.927) }{5} - \dfrac{25 (\cos 2\times 2.214 - \cos 2\times 0.927) }{2} - 16(2.214 - 0.927]\\

On solving, we have

\rightarrow \dfrac{1}{2} \times 7.499\\\\\rightarrow 3.75

Thus, the area of the region is 3.75 square units.

More about the area bounded by the curve link is given below.

brainly.com/question/24563834

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