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Rama09 [41]
4 years ago
8

Y + 2.3 = 0.45x

Mathematics
1 answer:
Irina18 [472]4 years ago
5 0
Multiply the first equation by 2:-
2y  + 4.6 = 0.90x
2y - 0.90x = -4.6
second equation is
-2y - 4.2x = -7.8
Adding:-
-5.1x =  -12.4
x = 2.4

-2y =  -7.8 + 4.2(2.4)  =  2.3
x = -1.2

Answer  x = 2.4 and y = -1.2

Its choice A

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Find the balance in the account after the given period. $2000 principal eating 5% compounded annually, 7 years
4vir4ik [10]
Formular is (principal *time*rate )/100 +principal
so applying that we have( 2000*5*7) +2000 which gives 2700 dollarss
8 0
3 years ago
Read 2 more answers
Circle P has a circumfrence of aproximately 75 inches what is the aproximate length of the radius, r? Use 3.14 for pi. Round to
ratelena [41]

Answer:

The approximate length of the radius, r is 12 inch.

Step-by-step explanation:

Given:

A circle P is given having circumference C,

C = 75 inch

pi = π = 3.14

radius = r

To Find:

radius = r = ?

Solution:

Circumference:

In geometry, the circumference (from Latin circumferens, meaning "carrying around") of a circle is the (linear) distance around it.

That is, the circumference would be the length of the circle if it were opened up and straightened out to a line segment.

Formula is given as

Circumference=2\pi (radius)

Substituting the values we get

75 = 2 × 3.14 × r

∴ r =\frac{75}{2\times 3.14}\\ \\r=\frac{75}{6.28} \\\\r=11.942\ inches

We approximate radius to

radius = 12 inich

7 0
3 years ago
Factor the expression
Alex777 [14]
Factor the equation using difference of squares, which says that a^2-2ab+b^2=(a-b)^2.

a is 2 since the square root of 4 is 2 and b is 5 because the square root of 25 is 5.

Final answer: (2x-5y)^2
8 0
3 years ago
WILL MARK BRAINLIEST!!! Thank youuu!!
Anna71 [15]

Answer:

(2p+9)^2

Step-by-step explanation:

We know this is a perfect square trinomial

a^2 +2ab +b^2 = (a+b)^2

a = 2p   b = 9

a^2 = 4p^2

2ab = 2*2p*9 = 36p

b^2 = 81

Check

4p^2 +36p+81 = (2p+9)^2

8 0
3 years ago
Which expression is equivalent to \frac{10q^5w^7}{2w^3}.\ \frac{4\left(q6\right)^2}{w^{-5}} for all values of q and w where the
mestny [16]

Answer:

\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}} =20q^{17}w^9

Step-by-step explanation:

Given

\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

Required

Determine the equivalent expression

\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

Simplify the first fraction

\frac{5q^5w^7}{w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

Apply law of indices on the first fraction;

5q^5w^{7-3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

5q^5w^4.\ \frac{4\left(q^6\right)^2}{w^{-5}}

\ \frac{5q^5w^4*4\left(q^6\right)^2}{w^{-5}}

Apply law of indices:

5q^5w^4*4\left(q^6\right)^2 * w^{5}

Evaluate the bracket

5q^5w^4*4 * q^{12} * w^{5}

Collect Like Terms

5*4q^5* q^{12}*w^4  * w^{5}

20q^5* q^{12}*w^4  * w^{5}

20q^{5+12}*w^{4+5}

20q^{17}w^9

Hence:

\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}} =20q^{17}w^9

7 0
3 years ago
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