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Gekata [30.6K]
2 years ago
10

Find the side lengths the cube X

Mathematics
1 answer:
s344n2d4d5 [400]2 years ago
7 0

Answer:

x = 6

Step-by-step explanation:

The volume (V) of the triangular prism is calculated as

V = Al ( A is the area of the triangular end and l is its length )

A = \frac{1}{2} bh = 0.5 × 9 × 4 = 18 cm² , then

V = 18 × 12 = 216 cm³

The volume of a cube is

V = s³ ( s is the side length ) , so

s³ = x³ = 216 ( take the cube root of both sides )

x = \sqrt[3]{216} = 6

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Some one pleae help!
Aleksandr-060686 [28]

Answer: \frac{61}{70}

Step-by-step explanation:

<em>let's take the two given distances and add them together</em>

<em />\frac{3}{10}+\frac{4}{7}<em />

<em>Now let's make give them a common denominator of 70</em>

<em>To do this we need to multiply </em>\frac{3}{10} (\frac{7}{7} ) and \frac{4}{7} (\frac{10}{10})<em />

<em />\frac{21}{70}+\frac{40}{70}<em />

<em />\frac{61}{70}<em />

7 0
2 years ago
Find the LCD of the fractions, and then simplify the expression. Assume that no denominator equals zero. 5/(3x^2y) - 4/(6xy^3
tamaranim1 [39]
The LCD = 6x^2y^3    ( because LCD of 3 and 6 = 6,  LCD of x^2 and x = x^2 and LCD of y and y^3 = y^3)

now divide 3x^2y into the LCD  then multiply this  by 5 to get the first term in the numerator  and do similar process to get second term, so we get:-

5(2y^2) - 4(x)
------------------
   6x^2y^3

=  2( 5y^2 - 2x)
   -----------------
        6x^2y^3

=    5y^2 - 2x
      -----------
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Which number is a common factor of 27 and 45?<br> A) 5 <br> B) 9 <br> C) 12 <br> D) 15
mestny [16]

Answer:

We found the factors and prime factorization of 27 and 45. The biggest common factor number is the GCF number. So the greatest common factor 27 and 45 is 9.

Step-by-step explanation:

6 0
3 years ago
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