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OverLord2011 [107]
4 years ago
9

Riley has a farm on a rectangular piece of land that is 200200200 meters wide. This area is divided into two parts: A square are

a where she grows avocados (whose side is the same as the length of the farm), and the remaining area where she lives.
Every week, Riley spends \$3$3dollar sign, 3 per square meter on the area where she lives, and earns \$7$7dollar sign, 7 per square meter from the area where she grows avocados. That way, she manages to save some money every week.



Write an inequality that models the situation. Use lll to represent the length of Riley's farm.
Mathematics
1 answer:
777dan777 [17]4 years ago
7 0

Answer:

The inequality that models the situation for her to have money to save is

7L² > 3(200L - L²)

On simplifying and solving,

L > 60 meters

Step-by-step explanation:

The length of her farm = L meters

The farm where she grows avocados is of square dimension

Area of the farm = L × L = L²

The piece of land is 200 m wide.

Total area of the piece of land = 200 × L = (200L) m²

If the area of her farm = L²

Area of the side where she lives will be

(Total area of the land) - (Area of the farm)

= (200L - L²)

= L(200 - L)

Every week, Riley spends $3 per square meter on the area where she lives, and earns $7 per square meter from the area where she grows avocados.

Total amount she earns from the side she grows the avocados = 7 × L² = 7L²

Total amount she spends on the side where she lives = 3 × (200L - L²) = 3(200L - L²)

For her to save money, the amount she earns must be greater than the amount she spends, hence the inequality had to be

(Amount she earns) > (Amount she spends)

7L² > 3(200L - L²)

To simplify,

7L² > 3L(200 - L)

Since L is always positive, we can divide both sides by L

7L > 3(200 - L)

7L > 600 - 3L

10L > 600

L > 60 meters

Hope this Helps!!!

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Answer:

There is no unique solution to this problem.

There are infinitely many solutions to this problem.

Step-by-step explanation:

Let B denotes broccoli crop

Let S denotes spinach crop

Last year, he grew 6 tons of broccoli per acre and 9 tons of spinach per acre, for a total of 93 tons of vegetables.

Mathematically,

6B + 9S = 93        eq. 1

This year, he grew 2 tons of broccoli per acre and 3 tons of spinach per acre, for a total of 31 tons of vegetables.

Mathematically,

2B + 3S = 31

2B = 31 -  3S

B = (31 -  3S)/2      eq. 2

Substitute eq. 2 into eq. 1

6B + 9S = 93

6[(31 -  3S)/2] + 9S = 93

3(31 -  3S) + 9S = 93

93 - 9S + 9S = 93

- 9S + 9S = 93 - 93

0 = 0

Therefore, there is no unique solution to this problem.

Which means that there are infinitely many solutions to this problem.

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3 years ago
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S=n(a1+an)/2 gives the partial sum of an arithmetic sequence. What is the formula solved for an?
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6 0
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Vertically opposite angles are equal
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5 0
4 years ago
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2) Fill in an angle measure greater than 100 degrees for the missing angle in yellow below. You will fill
timama [110]

Answer:

m∠a = 110°

m∠b = 110°

m∠c = 70°

m∠d = 70°

m∠i = 110°

m∠h = 110°

m∠j = 70°

m∠g = 110°

m∠f = 70°

m∠e = 70°

m∠k = 57°

m∠m = 70°

m∠l = 167°

Step-by-step explanation:

Let the measure of the yellow angle = 110°

Therefore;

m∠a = 110°  by vertically opposite angles

m∠b = m∠a = 110° by opposite interior angles of a parallelogram

m∠c = 180° - 110° = 70° by same side interior angles

m∠d = m∠c = 70° by opposite interior angles of a parallelogram

m∠i and m∠c are supplementary angles, therefore, m∠i = 110°

m∠h = m∠i = 110° by vertically opposite angles

m∠j = m∠c = 70° by vertically opposite angles

m∠g and m∠d are supplementary angles, therefore, m∠g = 110°

m∠f = m∠d = 70° by alternate interior angles

m∠f = m∠e = 70° by vertically opposite angles

m∠k = 180° - (m∠h + 13°) = 180° - (110° + 13°) = 57°

m∠b and m∠m are supplementary angles, therefore, m∠m = 70°

m∠l and 13° are supplementary angles, therefore, m∠l = 167°

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3 years ago
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