We can simplify it a bit
oh wait,
remember taht x^0=1, no matter what x is
we see the whole thing is to the zero power
the whole thing is equal to 1
doesn't matter what x or y is
the whole thing evaluates to 1
The probability that it also rained that day is to be considered as the 0.30 and the same is to be considered.
<h3>
What is probability?</h3>
The extent to which an event is likely to occur, measured by the ratio of the favorable cases to the whole number of cases possible.
The probability that the temperature is lower than 80°F and it rained can be measured by determining the number at the intersection of a temperature that less than 80°F and rain.
So, This number is 0.30.
Hence, we can say that it was less than 80°F on a given day, the probability that it also rained that day is 0.30.
To learn more about the probability from the given link:
brainly.com/question/18638636
The above question is incomplete.
The conditional relative frequency table was generated using data that compared the outside temperature each day to whether it rained that day. A 4-column table with 3 rows titled weather. The first column has no label with entries 80 degrees F, less than 80 degrees F, total. The second column is labeled rain with entries 0.35, 0.3, nearly equal to 0.33. The third column is labeled no rain with entries 0.65, 0.7, nearly equal to 0.67. The fourth column is labeled total with entries 1.0, 1.0, 1.0. Given that it was less than 80 degrees F on a given day, what is the probability that it also rained that day?
#SPJ4
Answer:
yes I agree with teacher
Step-by-step explanation:
I I think this because 1 people that have a phone and a computer are the highest group and two becauseit seems that most of the class has a phone it also seems that most of the class has a computer
Answer:
∠ 2 = 104°
Step-by-step explanation:
Since the trees are parallel, then
∠ 2 and 76° are same- side interior angles and are supplementary, thus
∠ 2 + 76° = 180° ( subtract 76° from both sides )
∠ 2 = 104°
Answer: 26
There’s nothing here for me to solve
