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Kay [80]
3 years ago
14

What are the x-intercepts of the graph y=f(x+4)

Mathematics
1 answer:
Sergio [31]3 years ago
5 0
The graph is y=x+4, to get the x-intercept we let y=0; and solve for x
thus we shall have:
0=x+4
subtract 4 from both sides
0-4=x+4-4
-4=x
hence the x-intercept will be at point (-4,0)


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Can you help I’ll mark brainliest
Marta_Voda [28]

Answer:

7\sqrt{3}

Step-by-step explanation:

Since this is a 30-60-90 triangle, we know that the sides have the following characteristic:

The side opposite to 30 degree angle: n

The side opposite to 60 degree angle: n\sqrt{3}

The side opposite to 90 degree angle: 2n

Since we know that 7 is opposite to 30-degree, and x is opposite to 60 degree, than we know that x = 7\sqrt{3}

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MULTIPLE CHOICE
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Step 1) Multiply 2 by 3

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Step 2) Combine like terms

<em>5x+6 = 5x+6</em>

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The table shows the heights of students in a group.
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Step-by-step explanation:

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Read 2 more answers
In a recent year, Washington State public school students taking a mathematics assessment test had a mean score of 276.1 and a s
Oksi-84 [34.3K]

Answer:

a) \mu_{\bar x} =\mu = 276.1

\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3

b) From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)

c) P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)

P(Z\geq2.070)=1-P(Z

Step-by-step explanation:

Let X the random variable the represent the scores for the test analyzed. We know that:

\mu=E(X) = 276.1 , \sigma=Sd(X) = 34.4

And we select a sample size of 64.

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Part a

For this case the mean and standard error for the sample mean would be given by:

\mu_{\bar x} =\mu = 276.1

\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3

Part b

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)

Part c

For this case we want this probability:

P(\bar X \geq 285)

And we can use the z score defined as:

z=\frac{\bar x -\mu}{\sigma_{\bar x}}

And using this we got:

P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)

And using a calculator, excel or the normal standard table we have that:

P(Z\geq2.070)=1-P(Z

8 0
3 years ago
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