Answer: D. Divide 5 by 1,200
Step-by-step explanation:
I know the answer
Haleemah needs to buy at least 4 packages of plates
Answer:
An exterior angle of a triangle is equal to the sum of the two remote
Step-by-step explanation:
2 a b c. 13. 10 z. 169 100 z. 269 z z. 269 16.4. +. = +. = +. = = = ≈. 3 – 4 – 5 x6 x6 x6 ... x 12. = = = = w y z x.
Since we have reflected only across the y-axis we know the x-values stay the same (but since they are changing quadrants will become positive) and the same goes for the y-values. Only the negative/positive area will change. Lets get to work:
<em>P(-2, -4) will become P'(2, -4)</em>
<em>Q(-3, -1) will become Q'(3, -1)</em>
<em>R(-4, -4) will become R'(4, -4)</em>
After doing this for a while you will be able to find the reflected coordinates without any trouble or graph.
<u>Key point</u><u>: Values stay the same</u>
Answer:
![y=-2x-4](https://tex.z-dn.net/?f=y%3D-2x-4)
Step-by-step explanation:
<u>Perpendicular Bisector</u>
The bisector of a segment defined by points (x1,y1) and (x2,y2) must pass by the midpoint of the segment.
The midpoint (xm,ym) is calculated as follows:
![\displaystyle x_m=\frac{x_1+x_2}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x_m%3D%5Cfrac%7Bx_1%2Bx_2%7D%7B2%7D)
![\displaystyle y_m=\frac{y_1+y_2}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y_m%3D%5Cfrac%7By_1%2By_2%7D%7B2%7D)
The endpoints of the segment are (-3,-8) and (5,-4), thus the midpoint M is:
![\displaystyle x_m=\frac{-3+5}{2}=1](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x_m%3D%5Cfrac%7B-3%2B5%7D%7B2%7D%3D1)
![\displaystyle y_m=\frac{-8-4}{2}=-6](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y_m%3D%5Cfrac%7B-8-4%7D%7B2%7D%3D-6)
Midpoint: M(1,-6)
Let's find the slope of the given segment. The slope can be calculated with the formula:
![\displaystyle m_1=\frac{y_2-y_1}{x_2-x_1}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20m_1%3D%5Cfrac%7By_2-y_1%7D%7Bx_2-x_1%7D)
![\displaystyle m_1=\frac{-4+8}{5+3}=\frac{1}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20m_1%3D%5Cfrac%7B-4%2B8%7D%7B5%2B3%7D%3D%5Cfrac%7B1%7D%7B2%7D)
If the bisector is also perpendicular, its slope m2 and the slope of the segment m1 must comply:
![m_1.m_2=-1](https://tex.z-dn.net/?f=m_1.m_2%3D-1)
Solving for m2:
![\displaystyle m_2=-\frac{1}{m_1}=-\frac{1}{\frac{1}{2}}=-2](https://tex.z-dn.net/?f=%5Cdisplaystyle%20m_2%3D-%5Cfrac%7B1%7D%7Bm_1%7D%3D-%5Cfrac%7B1%7D%7B%5Cfrac%7B1%7D%7B2%7D%7D%3D-2)
Once we have the slope -2 and the point through which our line must pass (1,-6), we compute the equation in its point-slope form:
![y-y_o=m(x-x_o)](https://tex.z-dn.net/?f=y-y_o%3Dm%28x-x_o%29)
![y-(-6)=-2(x-1)](https://tex.z-dn.net/?f=y-%28-6%29%3D-2%28x-1%29)
Operating
![y+6=-2(x-1)](https://tex.z-dn.net/?f=y%2B6%3D-2%28x-1%29)
![y+6=-2x+2](https://tex.z-dn.net/?f=y%2B6%3D-2x%2B2)
Rearranging
![\boxed{y=-2x-4}](https://tex.z-dn.net/?f=%5Cboxed%7By%3D-2x-4%7D)