Step-by-step explanation:
1.828 x 10 ^3 is standard for 1828
Answer:
48cm
Step-by-step explanation:
8 x 6
Answer:
Step-by-step explanation:
The mean SAT score is , we are going to call it \mu since it's the "true" mean
The standard deviation (we are going to call it ) is
Next they draw a random sample of n=70 students, and they got a mean score (denoted by ) of
The test then boils down to the question if the score of 613 obtained by the students in the sample is statistically bigger that the "true" mean of 600.
- So the Null Hypothesis
- The alternative would be then the opposite
The test statistic for this type of test takes the form
and this test statistic follows a normal distribution. This last part is quite important because it will tell us where to look for the critical value. The problem ask for a 0.05 significance level. Looking at the normal distribution table, the critical value that leaves .05% in the upper tail is 1.645.
With this we can then replace the values in the test statistic and compare it to the critical value of 1.645.
<h3>since 2.266>1.645 we can reject the null hypothesis.</h3>
Answer:
I will need 26.4 pounds of the expensive nuts and 1.6 pounds of the cheap nuts.
Step-by-step explanation:
Since I have one type of nut that sells for $ 4.50 / lb and another type of nut that sells for $ 8.00 / lb, and I would like to have 28 lbs of a nut mixture that sells for $ 7.80 / lb, to determine how much of each nut will I need to obtain the desired mixture, the following calculation must be performed:
8 x 0.95 + 4.5 x 0.05 = 7.825
8 x 0.94 + 4.5 x 0.06 = 7.79
0.94 x 28 = 26.32
26.4 x 8 + 1.6 x 4.5 = 218.4
218.4 / 28 = 7.8
Thus, I will need 26.4 pounds of the expensive nuts and 1.6 pounds of the cheap nuts.
The function for conversions from Fahrenheit to Celsius is:
Celsius = (Fahrenheit - 32) x 5/9
C(76.1) = (76.1 - 32) x 5/9
= (44.1) x 5/9
= 24.5
Therefore, 76.1 degrees Fahrenheit = 24.5 degrees Celsius.