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vaieri [72.5K]
2 years ago
11

Ronald Sutter, an assembly line worker, earns $16.655 per hour. He typically works 36.225 hours per week. What is his usual stra

ight-time pay?
Mathematics
1 answer:
Nadusha1986 [10]2 years ago
7 0

His usual straight-time pay is $603.327375 per week

<h3>How to determine his usual straight-time pay?</h3>

The given parameters are

Rate = $16.655 per hour

Duration = 36.225 hours per week

His usual straight-time pay is calculated as

Usual pay = Rate * Duration

So, we have

Usual pay = $16.655 per hour * 36.225 hours per week

Evaluate the product

Usual pay = $603.327375 per week

Hence, his usual straight-time pay is $603.327375 per week

Read more about linear rates at

brainly.com/question/7040405

#SPJ1

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Nina is selling three types of energy bars at a market stall. She bought 60 Enerbars at 40p per bar and 200 Grainbars at 60p per
Serhud [2]

Answer:

Nina sold 24 Amazebars  Plz Mark Brainliest

Step-by-step explanation:

  Cost:

80 x 0.40 = 32

180x 0.30 = 54

40 x 0 = 0

Total = 86

Income

80 x 2.25 = 180

180 x 2.25 = 405

X x 2.25 = 2.25x

Total = 585 + 2.25x

How many did she sell:

553 = 585 - 86 + 2.25x

553 = 499 + 2.25x

553 - 499 = 2.25x

54 = 2.25x

54/2.25 = x

24 = x

5 0
2 years ago
You earn a base fee plus an hourly rate for running errands.You earn 20$ when it takes 1 hour to run the errands. You earn $35 w
beks73 [17]

Answer:

<em>The base fee is 5</em>

Step-by-step explanation:

<u>Linear Function</u>

The linear function is widely used to model real situations in life where the dependancy of one variable are linear by nature.

The problem gives us three conditions, more than enough to find a linear model for the earnings for running errands. Let's make x the number of hours it takes to run the errands, and y the earnings. The linear model has the general equation

y=mx+b

We have these points (1,20) (2,35) (3,50) and need to find the base fee, which is the value of b or the independant term of the equation.

We'll use the first two points to find the equation and the third point to verify it. Using (1,20)

20=1\cdot m+b

m+b=20

Now we use (2,35)

35=m\cdot 2+b

2m+b=35

Subtracting both equations

m=15

Replacing into the first equation

b=5

The equation is

y=15x+5

Let's test the formula by replacing the point x=3

y=15\cdot 3+5=50

The model is accurate and the base fee is 5

6 0
4 years ago
Which of the functions below have period 2pi? Check all that apply. A. y = tan x B. y = sec x C. y = cot x D. y = csc x
Colt1911 [192]

Answer:

Option B and D are correct that is y=secx and  y=cscx  respectively.

Step-by-step explanation:

We have been given four functions:

CaseA:

y=tanx

\text{Period oftanx is} \pi

Hence, A is correct.

CaseB:

y=secx

\text{Period of secx is} 2\pi

Hence, B is correct.

CaseC:

y=cotx

\text{Period of cotx is} \pi

Hence, C is not correct.

CaseD:

y=cscx

\text{Period of cscx is} 2\pi

Hence, D is correct.

4 0
4 years ago
Read 2 more answers
Using a simulator at space​ camp, you practice landing your individual spaceship on landing platforms that have different shapes
Mila [183]

The Area of the platform is 33m²

Step-by-step explanation:

As the question says, the height of vertex from the base (D from AB) is 7m whereas the height of left vertex from the base (E from AB) is 4m

Thus it means the height of the Δ DCE (DX)= 7-4 ⇒3m

Since the platform is five-sided, the figure can be broken down into constituting parts

  1. Parallelogram ║ABCE
  2. Δ DCE

Are of the figure= Area of ║ABCE+ area Δ DCE

Area of ║ABCE= breadth * height

= 6*4 ⇒24m ²

Area Δ DCE= ½*(base)(height)

Putting the value of base is 6m and height as 3m

Area Δ DCE= ½*6*3

=9m ²

Total area= 24+9= 33m ²

3 0
3 years ago
The length of a bridge is 230 m. The length of each of Robert's paces is 75 cm.
wariber [46]

Answer:

307 paces

Step-by-step explanation:

First, lets convert Robert's pace to metres. (cm > m)

75cm = (75/100)m

= 0.75m

Number of Full Paces = Length of Bridge / 1 Full Pace

=

\frac{230m}{0.75m}  \\  = 306 \frac{2}{3} paces

See , we must have full paces, and in this case we are finding the minimum number of paces, so we will be looking at the lowest possible whole number, which in this case, is 307 paces.

5 0
2 years ago
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