Answer:
∠1 = 96°
∠2 = 84°
∠3 = 84°
Step-by-step explanation:
∠1 = 96°
∠2 = ∠3
∠1 + 96 + ∠2 + ∠3 = 360°
∠2 = (360 - 96 - 96)/2 = 84°
∠3 = 84°
Answer:
t = 4
Step-by-step explanation:
Given
+ 3 = 5 ( subtract 3 from both sides )
= 2
Multiply both sides by 2 to clear the fraction
t = 2 × 2 = 4
<u>EXPLANATION</u><u>:</u>
In ∆ ABC , ∠ABC = 40°
∠ACD is an exterior angle formed by extending BC to D
We know that
The exterior angle of a triangle formed by extending one side is equal to the sum of the opposite interior angles.
∠ACD = ∠CAB + ∠ABC
⇛50° = x° + 40°
⇛x° = 50°-40°
<h3>⇛x° = 10°</h3>
and
In ∆ ACD , AC = CD
⇛ ∠CDA = ∠CAD
Since the angles opposite to equal sides are equal.
Let ∠CDA = ∠CAD = A°
We know that
The sum of all angles in a triangle is 180°
In ∆ ACD,
∠CDA +∠CAD + ∠ACD = 180°
A°+A°+50° = 180°
⇛2A°+50° = 180°
⇛2A° = 180°-50°
⇛2A° = 130°
⇛A° = 130°/2
⇛A° = 65°
now,
∠CDA = ∠CAD = 65°
∠BAC + ∠CAD+y = 180°
Since angles in the same line
10°+65°+y = 180°
⇛75°+y =180°
⇛y = 180°-75°
<h3>⇛y = 105°</h3>
<u>Answer</u><u>:</u> Hence, the value of “x” & “y” will be 10° and 105° respectively.
The perimeter is just the sum of all of the outside edges
So, the perimeter is (2*14)+(2*7), or 28+14, or 42
So the perimeter of figure 1, with all of the information that you have given me, is 42 units
Answer:
Step-by-step explanation:
Start with h(t) = -16t^2 + initial height, which here is h(t) = -16t^2 + 1296. Set this = to zero, which corresponds to the object hitting the ground (h = 0):
0 = -16t^2 + 1296. Dividing all terms by -16, we get t^2 = 81, whose positive square root is 9. It takes 9 seconds for the object to hit the ground.