All categories

3 years ago

2 quarts = how many gallons

Mathematics

2 answers:

evablogger [386]3 years ago

7 0

Answer:

0.5 Gallons

Step-by-step explanation:

NeTakaya3 years ago

6 0

4 quarts is a gal, therefore 2 quarts is a half gal.

You might be interested in

Samantha’s college runs on a trimester schedule so she receives a bill 3 times a year for tuition. Each trimester costs $1,450,

matrenka [14]

3 times a year for 2 years is equal to 3 x 2, or 6. So we know that she will have to pay her bill 6 times.

The cost for each trimester is $1450, but we still have to add the book costs ($350). So, 1450 + 350 = 1800.

Now we know that she has to pay $1800 six times. So the equation will be:

1800 x 6 = 10800.

It will cost Samantha $10,800 to get her degree.

8 0

3 years ago

Read 2 more answers

Find the value of f(2) when f(x) = 4x+2

Sloan [31]

Answer:

the answer is 10

Step-by-step explanation:

f(2) that means the value of x= 2

the substitute x=2 in the 4(2)+2.Replace x with 2

6 0

3 years ago

What is the cheapest way to buy 48 cans of cola

Inga [223]

Answer:

both the first one

Step-by-step explanation:

use unit rate

4 0

3 years ago

Find the solution of the problem (1 3. (2 cos x - y sin x)dx + (cos x + sin y)dy=0.

lakkis [162]

Answer:

$2*sin(x)+y*cos(x)-cos(y)=C_1$

Step-by-step explanation:

Let:

$P(x,y)=2*cos(x)-y*sin(x)$

$Q(x,y)=cos(x)+sin(y)$

This is an exact differential equation because:

$\frac{\partial P(x,y)}{\partial y} =-sin(x)$

$\frac{\partial Q(x,y)}{\partial x}=-sin(x)$

With this in mind let's define f(x,y) such that:

$\frac{\partial f(x,y)}{\partial x}=P(x,y)$

and

$\frac{\partial f(x,y)}{\partial y}=Q(x,y)$

So, the solution will be given by f(x,y)=C1, C1=arbitrary constant

Now, integrate $\frac{\partial f(x,y)}{\partial x}$ with respect to x in order to find f(x,y)

$f(x,y)=\int\ 2*cos(x)-y*sin(x)\, dx =2*sin(x)+y*cos(x)+g(y)$

where g(y) is an arbitrary function of y

Let's differentiate f(x,y) with respect to y in order to find g(y):

$\frac{\partial f(x,y)}{\partial y}=\frac{\partial }{\partial y} (2*sin(x)+y*cos(x)+g(y))=cos(x)+\frac{dg(y)}{dy}$

Now, let's replace the previous result into $\frac{\partial f(x,y)}{\partial y}=Q(x,y)$ :

$cos(x)+\frac{dg(y)}{dy}=cos(x)+sin(y)$

Solving for $\frac{dg(y)}{dy}$

$\frac{dg(y)}{dy}=sin(y)$

Integrating both sides with respect to y:

$g(y)=\int\ sin(y) \, dy =-cos(y)$

Replacing this result into f(x,y)

$f(x,y)=2*sin(x)+y*cos(x)-cos(y)$

Finally the solution is f(x,y)=C1 :

$2*sin(x)+y*cos(x)-cos(y)=C_1$

7 0

3 years ago

Montel spends $0.75 every time he plays his favorite video game. If you have $10, write and resolve an inequality to calculate h

Bumek [7]

Answer:13.333333 repeating

Step-by-step explanation:money divided by how much the games cost

3 0

3 years ago