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serious [3.7K]
3 years ago
10

On a coordinate plane, 2 parallelograms are shown. Parallelogram 1 has points (0, 2), (2, 6), (6, 4), and (4, 0). Parallelogram

2 has points (2, 0), (4, negative 6), (2, negative 8), and (0, negative 2).
How do the areas of the parallelograms compare?

The area of parallelogram 1 is 4 square units greater than the area of parallelogram 2.
The area of parallelogram 1 is 2 square units greater than the area of parallelogram 2.
The area of parallelogram 1 is equal to the area of parallelogram 2.
The area of parallelogram 1 is 2 square units less than the area of parallelogram 2.

Mathematics
2 answers:
solmaris [256]3 years ago
8 0

Answer:

A

Step-by-step explanation:

zhuklara [117]3 years ago
4 0

Answer:

The answer is: A. The area of parallelogram 1 is 4 square units greater than the area of parallelogram 2.

Step-by-step explanation:

Hope this helped :)

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For this equation
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Find the surface area and show work
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Answer: 1,270in^2

Step-by-step explanation:

The surface area of a rectangle can be calculated with:

Area_{rectangle}=lenght*width

The surface area of a trapezoid can be calculated with:

Area_{trapezoid}=\frac{height}{2}(Larger\ base+Smaller\ base)

Calculate the area of the base, wich is a rectangle:

A_{1}=(34in)(15in)=510in^2

There are two equal rectangles, therefore, multiply the area of any of them by 2:

A_{2}=2(15in)(13in)=390in^2

Calculate the area of the other rectangle:

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There are two equal trapezoids, therefore, multiply the area of any of them by 2:

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Therefore, the surface area will be the sum of all the areas calculated:

SA=A_1+A_2+A_3+A_4\\\\SA=510in^2+390in^2+150in^2+220in^2\\\\SA=1,270in^2

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