On a coordinate plane, 2 parallelograms are shown. Parallelogram 1 has points (0, 2), (2, 6), (6, 4), and (4, 0). Parallelogram
2 has points (2, 0), (4, negative 6), (2, negative 8), and (0, negative 2).
How do the areas of the parallelograms compare?
The area of parallelogram 1 is 4 square units greater than the area of parallelogram 2.
The area of parallelogram 1 is 2 square units greater than the area of parallelogram 2.
The area of parallelogram 1 is equal to the area of parallelogram 2.
The area of parallelogram 1 is 2 square units less than the area of parallelogram 2.
How do the areas of the parallelograms compare?
The area of parallelogram 1 is 4 square units greater than the area of parallelogram 2.
The area of parallelogram 1 is 2 square units greater than the area of parallelogram 2.
The area of parallelogram 1 is equal to the area of parallelogram 2.
The area of parallelogram 1 is 2 square units less than the area of parallelogram 2.
2 answers:
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Answer:
second option
Step-by-step explanation:
Given
f(x) =
The denominator cannot be zero as this would make f(x) undefined.
Equating the denominator to zero and solving gives the value that x cannot be, that is
3x - 5 = 0 ⇒ 3x = 5 ⇒ x = ← excluded value
Thus domain is
(- ∞, ) u (
, ∞ )