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coldgirl [10]
3 years ago
8

Does this set of ordered pairs represent a function?

Mathematics
2 answers:
skelet666 [1.2K]3 years ago
6 0
Yes...because every x value corresponds to exactly one y value

a function will not have any repeating x values...it can have repeating y values, just not the x ones. So if all the x values are different, then it is a function
Lisa [10]3 years ago
4 0

Answer:

Option C is correct

Yes, the set of ordered pairs {(–5, –5), (–1, –2), (0, –2), (3, 7), (8, 9)}  represents the function.

because every x-value corresponds to exactly one y-value.

Step-by-step explanation:

A function states that it is a relation in which every domain value is paired with exactly one element of range.

Given the set of ordered pair:

{(–5, –5), (–1, –2), (0, –2), (3, 7), (8, 9)}

Domain is all the x-values, and range is all the y-values.

Domain: {-5, -1, 0, 3, 8}

Range:  {-5, -2, -2, 7, 9}

By definition:

each input value (i.e x values) is paired with exactly one element of y-value.

therefore,the set of ordered pairs {(–5, –5), (–1, –2), (0, –2), (3, 7), (8, 9)}  represents the function.

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8x^2-3 = sqrt(16x+9)
[8x^2-3]^2 = [sqrt(16x+9)]^2 ... square both sides
64x^4-48x^2+9 = 16x+9
64x^4-48x^2+9-16x-9 = 0
64x^4-48x^2-16x = 0
16x(4x^3-3x-1) = 0
16x(x-1)(2x+1)^2 = 0
16x=0 or x-1=0 or (2x+1)^2 = 0
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The possible solutions are x=0 or x=1 or x = -1/2

We need to check all the possible solutions

Checking x=0
8x^2-3 = sqrt(16x+9)
8(0)^2-3 = sqrt(16*0+9)
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The equation is false so x=0 is extraneous (not a real solution)

Checking x=1
8x^2-3 = sqrt(16x+9)
8(1)^2-3 = sqrt(16*1+9)
5 = 5
Equation is true. The value x=1 is a solution

Checking x=-1/2
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The equation is false so x=-1/2 is extraneous (not a real solution)

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