<h3>
1.Area of the parallelogram= 288 square units</h3><h3>
2.Area of the parallelogram=45 
</h3><h3>
3.Area of the trapezoid = 34 square in.</h3><h3>
4.Area of the trapezoid = 8 square ft</h3><h3>
5.Area of the rhombus= 27 square cm</h3><h3>
6.Area of the rhombus= 108 square in</h3><h3>
7.The area of the desktop is = 1200 square in</h3><h3>
8.The area of the rhombus is =84 
</h3><h3>
9.Area of the trapezoid = 240 square ft</h3>
Step-by-step explanation:
1.
Base =16 ft and Height = 18 ft
Area of the parallelogram = base × height
=16× 18 square units
= 288 square units
2.
Base = 9 m and height = 5 m
Area of the parallelogram = base × height
=(9×5) 
=45 
3 .
Height = 4 in and parallel sides are 12 in and 5 in
Area of the trapezoid =
square in.
= 34 square in.
4.
Height = 2 ft and parallel sides are 2 ft and 6 ft
Area of the trapezoid =
square ft
= 8 square ft
5.
Diagonals are 6 cm and 9 cm.
Area of the rhombus 
square cm
= 27 square cm
6. Diagonals are 12 in and 18 in
Area of the rhombus 
square in
= 108 square in
7. Given a desktop in the shape of a parallelogram has a base 30 in. and a height of 40 in
The area of the desktop is = (30 × 40 ) square in
= 1200 square in
8. Given , a rhombus has one diagonal that is 14 cm and other diagonal 12 cm.
The area of the rhombus =

=84 
9.Given , the base of trapezoid are 24 ft and 16 ft and height is 12 ft
Area of the trapezoid =
=
square ft
= 240 square ft
You just have to multiply 7 and 1 3/4 and you get 12.25 ounces
~Hope I Helped
The answers of the product is 1.8 * 0.63 = 1.134
Answer:
15°
Step-by-step explanation:
Since P is on the median of ΔABC, it is equidistant from points B and C as well as from C and Q. Thus, points B, C, and Q all lie on a circle centered at P. (See the attached diagram.)
The base angles (B and C) of triangle ABC are (180° -30°)/2 = 75°. This means arc QC of the circle centered at P has measure 150°. The diameter of circle P that includes point Q is defined to intersect circle P at R.
Central angle RPC is the difference between arcs QR and QC, so is 180° -150° = 30°. Inscribed angle RQC has half that measure, so is 15°. Angle PQC has the same measure as angle RQC, so is 15°.
Angle PQC is 15°.