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Alona [7]
3 years ago
10

How can I solve this problems?

Mathematics
1 answer:
nadezda [96]3 years ago
7 0
1)
Julia = Sj = 30,500 + 500n
Aysha = Sa = 26,000 + 1000n

when will
Sj = Sa
30,500 + 500n = 26,000 + 1000n
30,500 - 26,000 = 1000n - 500n
4,500 = 1000n - 500n
4,500 = 500n
n = 9
so they will have same salary after 9 years

2) X + Y = 8000
5%X + 3.25%Y = 312.5

X = 8000 - Y
0.05 ( 8000 - Y ) + 0.0325Y = 312.5
400 - 0.05Y + 0.0325Y = 312.5
400 - 0.0275Y = 312.5
400 - 312.5 = 0.0275Y
87.5 = 0.0275Y
Y = 3,181.81
X = 8000 - Y = 8000 - 3,181.81 = 4,818.19

3) X + Y = 3050
8%X + 7.5%Y = 234

X = 3050 - Y
0.08(3050 - Y) + 0.075Y = 234
244 - 0.08Y + 0.075Y = 234
244 - 234 = 0.025Y
Y = 400
X = 3050 - Y = 3050 - 400 = 2650



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Why are mathematicians like airlines?
ipn [44]
They both use planes.
8 0
3 years ago
Given h(x) = 4x + 3, find h(-1)<br>​
dsp73

Answer:

-1

Step-by-step explanation:

4x-1=-4

-4+3=-1

7 0
3 years ago
1.) What is the equation of the path of firework #1? Write your equation in general form.
valina [46]

1. I'm assumig that the paths are perfect parabolas

this means that their general forms can be written in y=ax^2+bx+c

it's easier to find vertex form first then expand to get general form

vertex form is y=a(x-h)^2+k where the vertex is (h,k) and a is a constant


firework #1

vertex is (10,50), so (h,k)=(10,50) and h=10, k=50

h_1=a(t-10)^2+50

to find the value of a, subsitute another point

(0,0)

0=a(0-10)^2+50)

0=100a+50

a=\frac{-1}{2}

so the equation in vertex form is h_1=\frac{-1}{2}(t-10)^2+50

expand to get general form

h_1=\frac{-1}{2}(t^2-20t+100)+50

h_1=\frac{-1}{2}t^2+10t-50+50

h_1=\frac{-1}{2}t^2+10t





2.

same as last time

vertex is (10,72) so (h,k)=(10,72) so h=10 and k=72

equation is h_2=a(t-10)^2+72

find a

use another point

(0,22)

22=a(0-10)^2+72

22=100a+72

-50=100a

a=\frac{-1}{2}

so the equation in vertex form is h_2=\frac{-1}{2}(t-10)^2+72




3.

range is the numbers that h is allowed to be

think about what h represents. it represents the height of the rocket

from the graph, we can see that the lowest possible height is 0yd and the highest height is 50yd

so range is 0 to 50 or 0≤h≤50


domain is the numbers that t is allowed to be

think about what t represents. it represents how long the rocket has been flying

it will stop flying when it hits the ground or at t=20

it starts flying at t=0

so domain is from 0 to 20 or 0≤t≤20

3 0
3 years ago
24 miles in T hours, 32 miles in T hours
lesantik [10]
Whatvis the question?
8 0
3 years ago
What is the measure of RPQ
patriot [66]

Answer:

239

Step-by-step explanation:

SP is the diameter so Arc RP is supplementary to Arc SR

31 + x = 180

x = 149

Arc PQ is supplementary to Arc SQ so

90 +  x = 180

x = 90

Arc Addition:

149 + 90 = 239

8 0
3 years ago
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