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weqwewe [10]
3 years ago
11

Jake was in a bicycle race. his average speed was 22 miles per hour. at this rate, how many feet per hour did jake travel?

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
8 0
<span>Since there are 5280 feet per mile:
22 miles/hr * 5280 feet/mile
= 116160 feet per hour
</span>
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Keith left his house, rode his bike 3 miles along one road, took a 90 degree turn, and rode 3 miles to the local swimming pool.
Sergio039 [100]
For this case we can model the problem as a rectangle triangle.
 We know:
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 We want to know:
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he would have saved:
 
1.8 miles

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3 years ago
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Max correctly solved this inequality.
pentagon [3]

Answer:

Answer:

See the graph attached. The red arrow represents the shaded area.

Explanation:

The inequality and its solution are given:

     

The solution set is all real numbers less than or equal to -50.

In a number line, the values less than -50 are all the values that are to the left of -50. Thus, the graph of a ≤ -50 must include -50 and the region to the left of it.

To indicate that - 50 is included, draw a solid point; then, shade the region since it to its left.

Please, see the graph attached. The red arrow represents the shaded area.

Step-by-step explanation:

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Please help w/ this question <br><br> image attached
vladimir2022 [97]

I think it’s 180 sorry if it’s wrong
5 0
3 years ago
1/2 +2/3=?<br> What's the answer?
11111nata11111 [884]
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7 0
3 years ago
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Algebra!!!<br> 3 Questions Only take if you know ALL Answers<br> PLZZZ QUICK
vitfil [10]

Answer:

1. -7.5

2. $1

3. 40

Step-by-step explanation:

For number 1, it can be solved by using the PEMDAS method, or see explanation below:

6x - 4x - 36 = 6 - 2x

2x - 36= -2x + 6

4x + 36 = 6

4x = -30

x = -15/2 or -7.5

For number 2, substitute 3 into both equations:

f(x) =1.50(3) + 2.00

and

f(x) = 2.00(3) + 1.50

This would get $6.50 and $7.50, which, if subtracted, gets $1.

For number 3, do something similar to the previous problem. Substitute 3 for x. It would be 5(2^3), or 40.

Hope this helps!

7 0
3 years ago
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