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In-s [12.5K]
2 years ago
5

The product of 7 and a nimber increased by 3 is equal to twice the number subtracted from 39

Mathematics
1 answer:
miss Akunina [59]2 years ago
7 0
Let the number is = x

So number increased by 3 is = x+3.

So product of 7 and (x+3) is = 7*(x+3).

Twice of number is = 2x

So we can write 

7(x+3) = 39 - 2x

7x + 21 = 39 - 2x

Now we can arrange the term as

7x + 2x = 39 - 21

9x = 18

x = 2.

SO the number is 2.
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Read 2 more answers
Please Answer <br><br> This is due by tomorrow night and I need help
labwork [276]

Answer:

AY = 16

IY = 9

FG = 30

PA = 24

Step-by-step explanation:

<em>The </em><em>centroid </em><em>of the triangle </em><em>divides each median</em><em> at the ratio </em><em>1: 2</em><em> from </em><em>the base</em>

Let us solve the problem

In Δ AFT

∵ Y is the centroid

∵ AP, TI, and FG are medians

→ By using the rule above

∴ Y divides AP at ratio 1: 2 from the base FT

∴ AY = 2 YP

∵ YP = 8

∴ AY = 2(8)

∴ AY = 16

∵ PA = AY + YP

∴ AP = 16 + 8

∴ AP = 24

∵ Y divides TI at ratio 1: 2 from the base FA

∴ TY = 2 IY

∵ TY = 18

∴ 18 = 2

→ Divide both sides by 2

∴ 9 = IY

∴ IY = 9

∵ Y divides FG at ratio 1:2 from the base AT

∴ FY = 2 YG

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∴ 20 = 2 YG

→ Divide both sides by 2

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∴ YG = 10

∵ FG = YG + FY

∴ FG = 10 + 20

∴ FG = 30

5 0
3 years ago
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