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My name is Ann [436]
3 years ago
12

Which fraction is equivalent to 2/6?

Mathematics
1 answer:
podryga [215]3 years ago
6 0

Answer: The second choice.

Step-by-step explanation: I don't believe anyone will read this and I don't want to waste my time typing this pointless explanation.

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The school you want to go to has an acceptance rate of 15%. That means that 15% of the students who apply to the school get in.
lisov135 [29]
12,000 Students Applied...

To find the answer, consider that for every 1000 students that apply, 150 students are accepted.

Divide 1800 by 150 and you get 12....which can be translated to 12,000 students

4 0
3 years ago
Find the solution of the differential equation that satisfies the given initial condition. dy/dx=x/y , y(0)=-1
Charra [1.4K]

Separating variables, we have

\dfrac{dy}{dx} = \dfrac xy \implies y\,dy = x\,dx

Integrate both sides.

\displaystyle \int y\,dy = \int x\,dx

\dfrac12 y^2 = \dfrac12 x^2 + C

Given that y(0)=-1, we find

\dfrac12 (-1)^2 = \dfrac12 0^2 + C \implies C = \dfrac12

Then the particular solution is

\dfrac12 y^2 = \dfrac12 x^2 + \dfrac12

y^2 = x^2 + 1

y = \pm\sqrt{x^2 + 1}

and because y(0)=-1, we take the negative solution to accommodate this initial value.

\boxed{y(x) = -\sqrt{x^2+1}}

7 0
2 years ago
How to solve complex number problem is x square + 2x +65=0
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Ill teach you how to do some of these things so you won't be having to use this site 
7 0
3 years ago
C = 14 a = 9 b = ?<br><br> if c is the hypotenuse of a right triangle, find the missing side.
NARA [144]
B = √(14² - 9²) = √(196-81) = √115 ≈ 10.7 units
6 0
3 years ago
In the game of blackjack played with one​ deck, a player is initially dealt 2 different cards from the 52 different cards in the
Volgvan

Answer:

P =4.83\%

Step-by-step explanation:

First we calculate the number of possible ways to select 2 cards an ace and a card of 10 points.

There are 4 ace in the deck

There are 16 cards of 10 points in the deck

To make this calculation we use the formula of combinations

nCr=\frac{n!}{r!(n-r)!}

Where n is the total number of letters and r are chosen from them

The number of ways to choose 1 As is:

4C1 = 4

The number of ways to choose a 10-point letter is:

16C1 = 16

Therefore, the number of ways to choose an Ace and a 10-point card is:

4C1 * 16C1 = 4 * 16 = 64

Now the number of ways to choose any 2 cards from a deck of 52 cards is:

52C2 =\frac{52!}{2!(52-2)!}

52C2 = 1326

Therefore, the probability of obtaining an "blackjack" is:

P = \frac{4C1 * 16C1}{52C2}

P = \frac{64}{1326}

P = \frac{32}{663}

P =0.0483

P =4.83\%

4 0
3 years ago
Read 2 more answers
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