Mine is pretty rough but hope it helps look at the attached image.
Ok so
what we do is
how much greater=wasted space=cylindervolume-conevolume
volume of a cinlinder=hpir^2
volume of a cone=(1/3)hpir^2
we can alread sybsitute something
(3/3)hpir^2-(1/3)hpir^2=(2/3)hpir^2
so wasted space=(2/3)hpir^2
diameter=4
d=2r
d/2=r
4/2=2=r
and 6=height
so
2/3(6)(3.14)(2^2)
4(3.14)(4)
16(3.14)
50.24 in^3 wasted
Answer:
6x^2 + 11x -1
Step-by-step explanation:
4x^2 + 9x + 2 + 2x^2 + 2x -3
Add the like terms to get the answer
Answer:
No answer do u today
Step-by-step explanation:
Lol
H hi ha job un hi is ihnihniuniunihn como te quiero
Answer:
35*
Step-by-step explanation:
IT IS THE SAME ANGLE