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algol13
3 years ago
9

Mr. Owens' printer can print 55 pages in 30 minutes. How many pages can it print In 1 hour?

Mathematics
1 answer:
miskamm [114]3 years ago
8 0

Answer:

110 pages

Step-by-step explanation:

The rate of 55 pg in 30 minutes is given in "minutes".

Thus,

we need to convert 1 hour to minutes.

We know 1 hour = 60 minutes

Note: 30 mins * 2 = 60 minutes

Logically, 30 minutes makes 55 pages, so 60 minutes (30 * 2) will make 55 * 2 = 110 pages

So, in 1 hour, it can print 110 pages (at this rate)

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The amount of Jake’s paycheck is directly proportional to the hours he works. After working 23 hours, his paycheck was $180.55.
vesna_86 [32]

Answer:

35 hours

Step-by-step explanation:

5 0
2 years ago
Amy ate of a pizza and Jack ate of a pizza. Which of the following is true?
pav-90 [236]

Answer:

c

Step-by-step explanation:

. portion of pizza eaten by Amy = portion of pizza eaten by Jack because it doesn't tell us information how much did they ate.

8 0
3 years ago
Vince worked 675 hours in 15 weeks. At what rate did he work in hours per week?​
NNADVOKAT [17]

Answer:

45 hours a week

Step-by-step explanation:

Ok, so we know that he worked 675 hours in 15 weeks.

So all we need to do is divide the hours by the amount of weeks, which is 15:

675/15= 45

So he worked 45 hours a week!

6 0
2 years ago
A one-tailed test is a a. hypothesis test in which rejection region is in one tail of the sampling distribution b. hypothesis te
garri49 [273]

Answer:

Option A) One tailed test is a hypothesis test in which rejection region is in one tail of the sampling distribution

Step-by-step explanation:

One Tailed Test:

  • A one tailed test is a test that have hypothesis of the form

H_0: \bar{x} = \mu\\H_A: \bar{x} < \mu\text{ or } \bar{x} > \mu

  • A one-tailed test is a hypothesis test that help us to test whether the sample mean would be higher or lower than the population mean.
  • Rejection region is the area for which the null hypothesis is rejected.
  • If we perform right tailed hypothesis that is the upper tail hypothesis then the rejection region lies in the right tail after the critical value.
  • If we perform left tailed hypothesis that is the lower tail hypothesis then the rejection region lies in the left tail after the critical value.

Thus, for one tailed test,

Option A) One tailed test is a hypothesis test in which rejection region is in one tail of the sampling distribution

6 0
2 years ago
A theater has a seating capacity of 750 and charges $3 for children, s5 for students, and $7 for adults. At a certain screening
-BARSIC- [3]

Answer:

Between 150 and 450

Step-by-step explanation:

We are going to find the number by resolving  a system of linear equations.

First we write the system equations :

C+S+A=750

Where C : children, S : students and A : adults

The equation represents the ''full attendance''

The second equation :

3C+5S+7A=3450

This equation represents the totaled receipts.

The system :

C+S+A=750\\3C+5S+7A=3450

has the following associated matrix :

\left[\begin{array}{cccc}1&1&1&750\\3&5&7&3450\end{array}\right]

By performing elementary matrix operations we find that the matrix is equivalent to

\left[\begin{array}{cccc}1&0&-1&150\\0&1&2&600\\\end{array}\right]

The new system :

C-A=150\\S+2A=600

Working with the equations :

C = 150 + A\\S = 600-2A

Our solution vector is :

\left[\begin{array}{c}C&S&A\end{array}\right] =\left[\begin{array}{c}150+A&600-2A&A\end{array}\right]

For example :

If 0 adults attended ⇒ A = 0

C = 150 + 0 \\C = 150\\S = 600 - 2A\\S = 600

This verify the totaled receipts equation :

150($3)+600($5) = $ 3450

A ≥ 0 ⇒ If A = 0 ⇒ C = 150

C = 150 is the minimum children attendance

From the equation :

S = 600 -2A

S ≥0

600 - 2A ≥ 0

600 ≥ 2A

300≥ A

A is restricted to the interval [ 0, 300]

When A = 0 ⇒ C = 150

When A = 300 ⇒C = 150 + A = 150 + 300 = 450

Children ∈ [ 150,450]

With C being an integer number (including 0)

Also S and A are integer numbers (including 0)

7 0
3 years ago
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