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den301095 [7]
3 years ago
9

Round 5,793 to the hundreds place using place value, benchmarks and midway points

Mathematics
1 answer:
dolphi86 [110]3 years ago
5 0
5,800 would be the answer when you round to the hundreds place
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The angles of a triangle are in the ratio of 2 : 12 : 16. The sum of all the angles in a triangle must equal 180 degrees. What i
UkoKoshka [18]

If the ratios are 2:12:16 the equation that should be used is 2x + 12x + 16x = 180.

First solve for x:

2x + 12x + 16x = 180

30x = 180

x = 6

Then plug x back in to find the degrees for each angle:

2x = 2(6) = 12

12x = 12(6) = 72

16x = 16(6) = 96

These are the degrees for each triangle: 12 degrees, 72 degrees, and 96 degrees which adds up to 180 degrees in total.

The equation, also at the top, is 2x + 12x + 16x = 180.


3 0
2 years ago
According to the Rational Root Theorem, which function has the same set of potential rational roots as the function g(x) = 3x^5
nata0808 [166]

Answer:

The correct option is A.

Step-by-step explanation:

The question is:

According to the Rational Root Theorem, which function has the same set of potential rational roots as the function g(x) = 3x5 – 2x4 + 9x3 – x2 + 12?

A).f(x) = 3x5 – 2x4 – 9x3 + x2 – 12

B).f(x) = 3x6 – 2x5 + 9x4 – x3 + 12x

C).f(x) = 12x5 – 2x4 + 9x3 – x2 + 3

D).f(x) = 12x5 – 8x4 + 36x3 – 4x2 + 48

Solution:

The function given to us is:

3x5 – 2x4 + 9x3 – x2 + 12

Find the factors of 12 and consider it as 'p'

The factors of 12 are:

p = +/- 1 , +/-2 , +/-3 , +/- 4 , +/-6

Now find the factors of 3 and consider it as 'q'

The factors of 3 are:

q = +/- 1 , +/- 3

We know that we write rational terms in p/q form.

Therefore the Rational roots are given by p/q

+/- 1 , +/-2 , +/-3 , +/- 4 , +/-6 , +/- 1/3 , +/- 2/3 , +/- 4/3

Now we will solve the first function given in part A.

f(x) = 3x^5 – 2x^4 - 9x^3 + x^2 - 12

Again find the factors of 12 and consider it as 'p'

The factors are:

p = +/- 1 , +/-2 , +/-3 , +/- 4 , +/-6

Now find the factors of 3 and consider it as 'q' .

q = +/- 1 , +/- 3

Rational root are given by p/q

+/- 1 , +/-2 , +/-3 , +/- 4 , +/-6 , +/- 1/3 , +/- 2/3 , +/- 4/3

Therefore the rational roots of the given function matches the rational roots of the given equation.

Hence the correct option is A

6 0
2 years ago
If ƒ={(5, 1),(6, 2),(7, 3),(8, 1),(9, 7)}, then the range of ƒ is {(1, 5),(2, 6),(3, 7),(1, 8),(7, 9)} {1, 2, 3, 7} {5, 6, 7, 8,
julsineya [31]
You need to just rewrite this
6 0
2 years ago
Eileen randomly chooses 15 seeds from the bag of flower seeds she has left over from last year, and 10 seeds from the bag she bo
amm1812
I believe it is D, stratified random sampling.
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5 0
3 years ago
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Which expression is equivalent to the following complex fraction? StartFraction 1 Over x EndFraction minus StartFraction 1 Over
Darina [25.2K]

Answer:

\frac{y-x}{x+y}

Step-by-step explanation:

We are given that fraction

\frac{\frac{1}{x}-\frac{1}{y}}{\frac{1}{x}+\frac{1}{y}}

We have to find the expression which is equivalent to given  fraction .

\frac{1}{x}-\frac{1}{y}=\frac{y-x}{xy}

\frac{1}{x}+\frac{1}{y}=\frac{x+y}{xy}

Substitute the values  then, we get

\frac{\frac{y-x}{xy}}{\frac{y+x}{xy}}

We know that

\frac{\frac{a}{b}}{\frac{x}{y}}=\frac{a}{b}\times \frac{y}{x}

Using the property then, we get

\frac{y-x}{xy}\times \frac{xy}{x+y}

\frac{y-x}{x+y}

This is required expression which is equivalent to given expression.

6 0
3 years ago
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