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3 years ago

12

2) Solve the equation 9x = 7(x + 2). A) - 7 B) -1 0 1 D) 7

2 answers:

Cerrena [4.2K]3 years ago

8 0

The answer is A)-7.
Because you distribute and then subtract 7x from both sides then simplify

Mars2501 [29]3 years ago

5 0

Answer:

C. 1

Step-by-step explanation:

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Somebody please help me

WITCHER [35]

Step-by-step explanation:

x - 1 = - 3x - 14

Bringing like terms on one side

x + 3x = -14 + 1

4x = - 13

x = - 13/4

5 0

3 years ago

May I please get some help?

Vladimir79 [104]

I think its 80 m3 or either 18 m3

3 0

3 years ago

Read 2 more answers

In the pic thank you guys

Ahat [919]

Answer:

The soda costs 2.20 and the sandwich costs 7.70

Step-by-step explanation:

To find this, set the soda cost as x. We now know that the sandwich cost is 3.5x. Add these together and set equal to 9.90

x + 3.5x = 9.90

4.5x = 9.90

x = 2.20

This is the cost of the soda. Now we can multiply that by 3.5 to get the sandwich cost.

3.5 * 2.20 = 7.70

7 0

3 years ago

Let Q(x, y) be the predicate "If x < y then x2 < y2," with domain for both x and y being R, the set of all real numbers.

Levart [38]

Answer:

a) Q(-2,1) is false

b) Q(-5,2) is false

c)Q(3,8) is true

d)Q(9,10) is true

Step-by-step explanation:

Given data is $Q(x,y)$ is predicate that $x$ then $x^{2}$ . where $x,y$ are rational numbers.

a)

when $x=-2, y=1$

Here $-2$ that is $x$ satisfied. Then

$(-2)^{2}$

$4$ this is wrong. since $4>1$

That is $x^{2}$ $>y^{2}$ Thus $Q(x,y)$ $=Q(-2,1)$ is false.

b)

Assume $Q(x,y)=Q(-5,2)$ .

That is $x=-5, y=2$

Here $-5$ that is $x$ this condition is satisfied.

Then

$(-5)^{2}$

$25$ this is not true. since $25>4$ .

This is similar to the truth value of part (a).

Since in both $x$ satisfied and $x^{2} >y^{2}$ for both the points.

c)

if $Q(x,y)=Q(3,8)$ that is $x=3$ and $y=8$

Here $3$ this satisfies the condition $x$ .

Then $3^{2}$

$9$ This also satisfies the condition $x^{2}$ .

Hence $Q(3,8)$ exists and it is true.

d)

Assume $Q(x,y)=Q(9,10)$

Here $9$ satisfies the condition $x$

Then $9^{2}$

$81$ satisfies the condition $x^{2}$ .

Thus, $Q(9,10)$ point exists and it is true. This satisfies the same values as in part (c)

6 0

3 years ago

If the ratio of beakers to test tubes in a lab is 3:8, and there are 64 test tubes, how many beakers are there?

OLga [1]

3:8
Beakers: test tubes

3+8=15

64/15= 4

3:4. X4
12:16

12 beakers

Please mark brainiest :)

3 0

3 years ago

Read 2 more answers