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vampirchik [111]
3 years ago
10

If this figure is reflected across the x-axis, what is the orientation of the reflected figure?

Mathematics
2 answers:
Naddika [18.5K]3 years ago
6 0
I'm pretty sure that would go down into the negatives.

il63 [147K]3 years ago
4 0

The answer is D, the last one.

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Thomas creates the table shown to represent the function ƒ(x) = x2 + 3x - 10. determine the zeros of the equation.
Eddi Din [679]
Answer: A

Explanation: The zeroes of f(x) are the value/s of x such that f(x) = 0. So, we need to find the values of x in the equation f(x) = 0.

Note that

f(x) = 0
⇔ x² + 3x - 10 = 0

By factoring into binomials, x² + 3x - 10 = (x + 5)(x - 2). Thus, 

x² + 3x - 10 = 0
⇔ (x + 5)(x - 2) = 0
⇔ x + 5 = 0 or x - 2 = 0
⇔ x = -5 or x = 2

Hence, the zeroes of x are  -5 and 2. 
4 0
3 years ago
Need help plz..........
boyakko [2]
Subtraction property of equality
2/3y = -6
2/3y × 3/2 = -6 × 3/2
multiplication property of equality
y = -9
8 0
3 years ago
A public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes. Kar
ch4aika [34]

Answer:

We conclude that the mean waiting time is less than 10 minutes.

Step-by-step explanation:

We are given that a public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes.

Karen took bus number 14 during peak hours on 18 different occasions. Her mean waiting time was 7.8 minutes with a standard deviation of 2.5 minutes.

Let \mu = <u><em>mean waiting time for bus number 14.</em></u>

So, Null Hypothesis, H_0 : \mu \geq 10 minutes      {means that the mean waiting time is more than or equal to 10 minutes}

Alternate Hypothesis, H_A : \mu < 10 minutes    {means that the mean waiting time is less than 10 minutes}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                       T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean waiting time = 7.8 minutes

             s = sample standard deviation = 2.5 minutes

             n = sample of different occasions = 18

So, <u><em>test statistics</em></u> =  \frac{7.8-10}{\frac{2.5}{\sqrt{18} } }  ~ t_1_7

                              =  -3.734

The value of t test statistics is -3.734.

Now, at 0.01 significance level the t table gives critical value of -2.567 for left-tailed test.

Since our test statistic is less than the critical value of t as -3.734 < -2.567, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that the mean waiting time is less than 10 minutes.

5 0
3 years ago
How long it will take 2000$ to double if it is invested at 6% interest compounded semi annually
katen-ka-za [31]

Answer:

Step-by-step explanation:

4 0
3 years ago
Write the equation of this graph in slope- intercept form<br>0,6 4,0​
zloy xaker [14]

Answer:

4 x − 5 + y = 0

x − y + 4 = 8

x + 6 y = 5

Step-by-step explanation:

7 0
2 years ago
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