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3 years ago

(69 points!) Some1 please solve. (69 points!)

Mathematics

1 answer:

MAVERICK [17]3 years ago

5 0

Answer:

for the second questio it is certainly The last choice D

Step-by-step explanation:

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Solve the equation for principal values of x. Express solutions in degrees.

Hitman42 [59]

Option C:

x = 90°

Solution:

Given equation:

$\sin x=1+\cos ^{2} x$

<u>To find the degree:</u>

$\sin x=1+\cos ^{2} x$

Subtract 1 + cos²x from both sides.

$\sin x-1-\cos ^{2} x=0$

Using the trigonometric identity: $\cos ^{2}(x)=1-\sin ^{2}(x)$

$\sin x-1-\left(1-\sin ^{2}x\right)=0$

$\sin x-1-1+\sin ^{2}x=0$

$\sin x-2+\sin ^{2}x=0$

$\sin ^{2}x+\sin x-2=0$

Let sin x = u

$u^2+u-2=0$

Factor the quadratic equation.

$(u+2)(u-1)=0$

u + 2 = 0, u – 1 = 0

u = –2, u = 1

That is sin x = –2, sin x = 1

sin x can't be smaller than –1 for real solutions. So ignore sin x = –2.

sin x = 1

The value of sin is 1 for 90°.

x = 90°.

Option C is the correct answer.

3 0

2 years ago

Read 2 more answers

Written as a simplified polynomial in standard form, what is the result when (3x-1)^2 is subtracted from 4?

nikklg [1K]

Answer:

3(x-1)x(3x+1)

Step-by-step explanation:

3 0

2 years ago

How much would $600 invested at 8% interest compounded continuously be worth after 3 years? Round your answer to the nearest cen

eduard

Answer:

yes

Step-by-step explanation:

You just do it

5 0

2 years ago

Which shows the correct substitution of the values a, b, and c from the equation 0 = 4x2 + 2x – 1 into the quadratic formula bel

neonofarm [45]

Answer:

x = StartFraction negative 2 plus or minus StartRoot 2 squared minus 4(4)(negative 1) EndRoot Over 2(4) EndFraction

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

$ax^2+bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^2-4ac} }{2a}$

in this problem we have

$4x^2 + 2x - 1=0$

$a=4$

$b=2$

$c=-1$

substitute in the formula

$x=\frac{-2(+/-)\sqrt{2^2-4(4)(-1)} }{2(4)}$

therefore

x = StartFraction negative 2 plus or minus StartRoot 2 squared minus 4(4)(negative 1) EndRoot Over 2(4) EndFraction

8 0

1 year ago

Read 2 more answers

Every prime number greater than 10 has a digit in the ones place that is include in wich set of numbers A- 1,3,7,9 B-1,3,5,9 D-1

marta [7]

That's very interesting. I had never thought about it before.
Let's look through all of the ten possible digits in that place,
and see what we can tell:

-- 0:
   A number greater than 10 with a 0 in the units place is a multiple of
   either 5 or 10, so it's not a prime number.

-- 1:
    A number greater than 10 with a 1 in the units place could be
    a prime (11, 31 etc.) but it doesn't have to be (21, 51).

-- 2:
   A number greater than 10 with a 2 in the units place has 2 as a factor
   (it's an even number), so it's not a prime number.

-- 3:
   A number greater than 10 with a 3 in the units place could be
   a prime (13, 23 etc.) but it doesn't have to be (33, 63) .

-- 4:
   A number greater than 10 with a 4 in the units place is an even
   number, and has 2 as a factor, so it's not a prime number.

-- 5:
   A number greater than 10 with a 5 in the units place is a multiple
   of either 5 or 10, so it's not a prime number.

-- 6:
   A number greater than 10 with a 6 in the units place is an even
   number, and has 2 as a factor, so it's not a prime number.

-- 7:
   A number greater than 10 with a 7 in the units place could be
   a prime (17, 37 etc.) but it doesn't have to be (27, 57) .

-- 8:
   A number greater than 10 with a 8 in the units place is an even
   number, and has 2 as a factor, so it's not a prime number.

-- 9:
   A number greater than 10 with a 9 in the units place could be
   a prime (19, 29 etc.) but it doesn't have to be (39, 69) .

So a number greater than 10 that IS a prime number COULD have
any of the digits 1, 3, 7, or 9 in its units place.

It CAN't have a 0, 2, 4, 5, 6, or 8 .

The only choice that includes all of the possibilities is 'A' .

4 0

2 years ago