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inessss [21]
2 years ago
13

Help me ASAP for this question.

Mathematics
2 answers:
o-na [289]2 years ago
8 0

Answer:

<6 and <8

<1 and <7

Step-by-step explanation:

Supplementary are angles that add up to 180 degrees. (A straight line)

zmey [24]2 years ago
7 0
The answers is 6 and 8
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If two lines are parallel which statement must be true? A.Their slopes are zero. B.Their slopes are negative reciprocals. C. The
stepan [7]

Answer:

D

Step-by-step explanation:

Parallel lines have the same gradient.

A line with a slope of zero is a horizontal line. Although two lines that have a slope of zero will result in two parallel lines, not all parallel lines are horizontal lines. Since the question is asking for which statement <u>must</u> be true, option A is incorrect.

If the slopes of two lines are negative reciprocals, they are perpendicular to each other. This is because the product of the gradients of 2 perpendicular lines is -1. Let the gradient of the first line be A and the other be B.

AB= -1

A =   - \frac{ 1}{B}

B =  -  \frac{1}{A}

Thus, option B is incorrect too.

Undefined slopes gives vertical lines. Like option A, if two lines have an undefined slope, they will be parallel to each other. However since parallel lines are nit necessarily vertical lines, option C is also incorrect.

4 0
2 years ago
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Find the area of shaded sector of the circle?
Y_Kistochka [10]
Tutu bskdnb dhdbdvrnir
8 0
3 years ago
Which of the following symbols indicates that a value is included in a solution set.
Ulleksa [173]
Answer: Filled in bubble
3 0
3 years ago
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where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤
marusya05 [52]

THIS IS THE COMPLETE QUESTION BELOW

The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.

Answer

$168.27

Step by step Explanation

Given p=90000/400+3x

With the limits of 40 to 50

Then we need the integral in the form below to find the average price

1/(g-d)∫ⁿₐf(x)dx

Where n= 40 and a= 50, then if we substitute p and the limits then we integrate

1/(50-40)∫⁵⁰₄₀(90000/400+3x)

1/10∫⁵⁰₄₀(90000/400+3x)

If we perform some factorization we have

90000/(10)(3)∫3dx/(400+3x)

3000[ln400+3x]₄₀⁵⁰

Then let substitute the upper and lower limits we have

3000[ln400+3(50)]-ln[400+3(40]

30000[ln550-ln520]

3000[6.3099×6.254]

3000[0.056]

=168.27

the average price p on the interval 40 ≤ x ≤ 50 is

=$168.27

8 0
3 years ago
Carli made 9 greeting
Leona [35]

Step-by-step explanation:

Shes wrong because she did it in 3 hours which means she would have made 3 cards and not 9.

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