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3 years ago

How many 4-digit numbers are possible if the hundreds digit is 8 and if repetition of digits is allowed?

1 answer:

7 0

There are 10 digits from 0 to 9
When you say 4 digit number that means it can't start with zero, then
1) there are 9 ways to chose the 1st digit (excluding zero)
2) there are only 1 ways to chose the 2nd digit (only 8))
3) there are 10 ways to chose the 3rd digit
4) there are 10 ways to chose the 4th digit

TOTAL NUMBER OF WAYS: 9 x 1 x 10 x 10 = 900

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How do i solve (3c^2d^4) ^3 x (2c^5d^8)^3?

vredina [299]

Answer:

$216c^{21}d^{36}$

Step-by-step explanation:

$(3c^2d^4)^3 * (2x^5d^8)^3$

$(3c^2)^3 (d^4)^3 * (2c^5)^3 (d^8)^3$

$27c^6 d^{12} * 8c^{15} d^{24}$

$216c^{21}d^{36}$

Hope this helps!

7 0

1 year ago

Pls can someone help me‼️‼️‼️‼️<br> and I don’t want files.

ANEK [815]

Answer:

135

Step-by-step explanation:

a line always has a degree of 180 so u just subtract 45 from 180 and get 135

5 0

2 years ago

Write an equation for the quadratic graphed below: x-intercepts: (-1,0) and (4,0); y-intercept: (0,1)

Luda [366]

Answer:

y = (1/4)x² - (5/4)x + 1

Step-by-step explanation:

The x-intercepts of the quadratic equation are simply it's roots.

Thus, we have;

(x + 1) = 0 and (x - 4) = 0

Now, formula for quadratic equation is;

y = ax² + bx + c

Where c is the y intercept.

At y-intercept: (0,1), we have;

At (-1,0), thus;

0 = a(1²) + b(1) + 1

a + b = -1 - - - (1)

At (4,0), thus;

0 = a(4²) + b(4) + 1

16a + 4b = -1

Divide both sides by 4 to get;

4a + b = -1/4 - - - (2)

From eq 1, b = -1 - a

Thus;

4a + (-1 - a) = -1/4

4a - 1 - a = -1/4

3a - 1 = -1/4

3a = 1 - 1/4

3a = 3/4

a = 1/4

b = -1 - 1/4

b = -5/4

Thus;

y = (1/4)x² - (5/4)x + 1

6 0

2 years ago

Simplify: 8/6/7 helpppppppppppp meeeeeeeeeeeee I will give you 100 points but only if you do right I will report if you play me

Naily [24]

Answer:

4/12??

Step-by-step explanation:

6 0

3 years ago

Find the value of x such that 365 based seven + 43 based x = 217 based 10.

Pepsi [2]

We need to find the base x in the following equation:

$365_7+43_x=217_{10}$

First, lets convert 365 from base 7 to base 10. This is given by

$365_7=3\times7^2+6\times7^1+5\times7^0$

where the upperindex denotes the position of eah number. This gives

$\begin{gathered} 365_7=3\times49+6\times7+5\times1 \\ 365_7=147+42+5 \\ 365_7=194_{10} \end{gathered}$

that is, 365 based 7 is equal to 194 bases 10.

Now, lets do the same for 43 based x. Lets convert 43 based x to base 10:

$43_x=4\times x^1+3\times x^0$

where again, the superindex 0 and 1 denote the position 0 and 1 in the number 43. This gives

$43_x=(4x+3)_{10}$

Now, we have all number in base 10. Then, our first equation can be written in base 10 as

$194_{10}+(4x+3)_{10}=217_{10}$

For simplicity, we can omit the 10 and get

$194+4x+3=217$

so, we can solve this equation for x. By combining similar terms. we have

$197+4x=217$

and by moving 197 to the right hand side, we obtain

$\begin{gathered} 4x=217-197 \\ 4x=20 \end{gathered}$

Finally, we get

$\begin{gathered} x=\frac{20}{4} \\ x=5 \end{gathered}$

Therefore, the solution is x=5

8 0

10 months ago