1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Arisa [49]
3 years ago
7

Orders for a computer are summarized by the optional features that are requested. The proportion of orders with no optional feat

ures is 0.29. The proportion of orders with one optional feature is 0.34. The proportion of orders with more than one optional feature is 0.37. (a) What is the probability that an order requests at least one optional feature? Round your answer to two decimal places (e.g. 98.76). (b) What is the probability that an order does not request more than one optional feature? Round your answers to two decimal places (e.g. 98.76).
Mathematics
1 answer:
Scorpion4ik [409]3 years ago
3 0

Answer:

(a) 71.00%

(b) 63.00%

Step-by-step explanation:

No optional features = 0.29

One feature = 0.34

Two features = 0.37

(a) The probability that an order requests at least one optional feature is 100% minus the probability of an order requesting no optional features:

P=1-0.29=0.71=71.00\%

(b) The probability that an order does not request more than one optional feature is 100% minus the probability of an order requesting two optional features:

P = 1 -0.37=0.63 = 63.00\%

You might be interested in
Select all the conditions for which it is possible to construct a triangle. (7.G.1.2) Group of answer choices a. A triangle with
saw5 [17]

Answer:

  b, d, e, f

Step-by-step explanation:

Here are the applicable restrictions:

  • The sum of angles in a triangle is 180°, no more, no less.
  • The sum of the lengths of the two shortest sides exceeds the longest side.
  • When two sides and the angle opposite the shortest is given, the sine of the given angle must be at most the ratio of the shortest to longest sides.

a. A triangle with angle measures 60°, 80°, and 80° (angle sum ≠ 180°, not OK)

b. A triangle with side lengths 4 cm, 5 cm, and 6 cm (4+5 > 6, OK)

c. A triangle with side lengths 4 cm, 5 cm, and 15 cm (4+5 < 15, not OK)

d. A triangle with side lengths 4 cm, 5 cm, and a 50° angle across from the 4 cm side (sin(50°) ≈ 0.766 < 4/5, OK)

e. A triangle with angle measures 30° and 60°, and an included 3 cm side length (OK)

f. A triangle with angle measures 60°, 20°, and 100° (angle sum = 180°, OK)

_____

<em>Additional comment</em>

In choice "e", two angles and the side between them are specified. As long as the sum of the two angles is less than 180°, a triangle can be formed. The length of the side is immaterial with respect to whether a triangle can be made.

__

The congruence postulates for triangles are ...

  SSS, SAS, ASA, AAS, and HL

These essentially tell you the side and angle specifications necessary to define <em>a singular triangle</em>. As we discussed above, the triangle inequality puts limits on the side lengths specified in SSS. The angle sum theorem puts limits on the angles when only two are specified (ASA, AAS).

In terms of sides and angles, the HL postulate is equivalent to an SSA theorem, where the angle is 90°. In that case, the angle is opposite the longest side (H). In general, SSA will specify a singular triangle when the angle is opposite the <em>longest</em> specified side, regardless of that angle's measure. However, when the angle is opposite the <em>shortest</em> specified side, the above-described ratio restriction holds. If the sine of the angle is <em>less than</em> the ratio of sides, then <em>two possible triangles are specified</em>.

4 0
2 years ago
What is a key purpose of using simulation when comparing two populations?
neonofarm [45]

Answer:

B) Observing how probability works with real items

Step-by-step explanation:

Just took the quiz

4 0
3 years ago
Factor completely, then place the factors in the proper location on the grid. a2 - 5a - 6
horrorfan [7]

Answer:

(a-6)(a+1)

Step-by-step explanation:

factor a2-5a-6

7 0
3 years ago
Quick question if I had a problem that was sin x = 18.9/20 =.945 how would I inverse sin of both sides ?
galben [10]

Answer:

The result is about 70.9 degrees

Step-by-step explanation:

Easy for a calculator.  If you're not using a calculator, it's much more tedious!

There is an inverse sine key on your calculator, but you may have to press a key (likely labeled 2nd or INV) first.  The attached image shows a TI-83 display.  To get the inverse sine, I first pressed the yellow 2nd key, then the sin key.

Check MODE first to make sure you're measuring angles in degrees (if that's what you want!).  Some calculators display angle mode with a small letter at the top of the display, D, R, or G usually.

The left side of the equation produces just x.

\sin{x}=.945\\\\\sin^{-1}(\sin{x})=\sin^{-1}(.945)\\x=\sin^{-1}(.945) \approx 70.9^\circ

6 0
2 years ago
Given that she wins the plumbing contract what is the probability that she wins the heating contract
Alexxx [7]
Nothing u cant do anything with a plumbing contract
5 0
3 years ago
Other questions:
  • What is the slope of the line represented by the equation –5x 2y= 10 ?
    14·1 answer
  • 11/15-3/5 in fraction
    13·1 answer
  • X^2 -9 = -15 i got decimals please help me
    15·2 answers
  • Distance from sun in au from mercury pls thanks
    13·1 answer
  • What does this expression represent five times the quotient of some number and ten
    11·1 answer
  • The sum of 3 times the value of x and 2 is equal to 4 less than 5 times the value x. Which equation can be used to find the valu
    7·2 answers
  • What is the probability of spinning green?
    12·1 answer
  • Slope is 2, and (3,8) is on the line.<br> Please help :(
    8·1 answer
  • 40 divided by a number m
    13·1 answer
  • On dividing x^3-3x^2+x+2 by a polynomial g(x), the quotient and remainder were x- 2 and "-2x+1" respectively, then g(x) is equal
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!