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Diano4ka-milaya [45]
3 years ago
14

Which of the following has a positive value? sec (2pi/3) tan (2pi/3) cos (2pi/3) csc (2pi/3)

Mathematics
1 answer:
Darya [45]3 years ago
7 0

Answer:  D) csc (2π/3)

<u>Step-by-step explanation:</u>

2π/3 is in Quadrant II

Quadrant II has a negative x-value and a positive y-value.

x-values are: cos & sec

y-values are: sin & csc

tan = y/x so will be negative in Quadrant II

A) sec = -

B) tan = -

C) cos = -

D) csc = +     this works!

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Volgvan
It would be the second answer. He starts with 2/3 cup, then take out 2 1/6 cup amounts, which make 2/6 cup. Since he's taking it out, you would subtract it from the original value. So you would get 2/3 cup minus 2/6 cup and to make the denominators equal you would multiply 2/3 cup by 2, so you would have 4/6 cup minus 2/6 cup which equals 2/6 cup.
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3 years ago
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Question 17 (5 points)
Elden [556K]

Answer:

The pet sitter babysat his dog for 3 hours.

Step-by-step explanation:

You know that a pet sitter charges $ 20 for supplies and $ 10 per hour of service, represented by the equation C = 10*n + 20, which describes the total cost she would charge for n hours of service.

The pet sitter charges a customer $ 50 for his service, so C has a value of $ 50.

Replacing:

50=10*n+20

Solving:

50 - 20= 10*n +20 -20

30= 10*n

30÷10= n

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<u><em>The pet sitter babysat his dog for 3 hours.</em></u>

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3 years ago
If New York is -15°, and Chicago is -10°, which city is colder?
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Step-by-step explanation:

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Write a polynomial function f of least degree that has a leading coefficient of 1 and the given zeros. Write the function in sta
NeX [460]

Answer:

f(x)=x^3+(3+\sqrt{5})x^2+(6\sqrt{5}-18)x

or

f(x)=x^3+3x^2+\sqrt{5}x^2-18x+6\sqrt{5}x

Step-by-step explanation:

A polynomial function with 3 zeroes is going to be of degree 3, so we're going to have at least least 3 factors of the form x-a, where <em>a </em>is a zero of the function. For three zeroes <em>a</em>, <em>b</em>, and <em>c</em>, we'd have the factors x-a,\ x-b, and x-c, making our function look like

f(x)=(x-a)(x-b)(x-c)

Substituting our roots for a, b, and c:

f(x)=(x-(-6))(x-0)(x-(3-\sqrt{5}))\\=(x+6)(x)(x-3+\sqrt{5})

To write this function in standard form, we can expand from left to right:

f(x)=(x^2+6x)(x-3+\sqrt{5})\\=(x^2+6x)x-(x^2+6x)3+(x^2+6x)\sqrt{5}\\=x^3+6x^2-3x^2-18x+\sqrt{5}x^2+6\sqrt{5}x\\=x^3+3x^2+\sqrt{5}x^2-18x+6\sqrt{5}x

At this point, we could either leave it as is, or group the coefficients for the x^2 and x terms to get

f(x)=x^3+(3+\sqrt{5})x^2+(6\sqrt{5}-18)x

7 0
4 years ago
The first bus stop on a bus route is 4 miles from school how many yards is the first bus stop from school
Aleksandr [31]
7,040 Yards because there is 1760 yards in a mile.
1760 x 4 = 7,040
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