We can represent the width as x and the length as x+5. Then we can make the area formula A=(x)*(x+5), plug in 36 for A, and solve for x
36=x^2+5x (distribute)
0=x^2+5x-36
0=(x+9)(x-4)
So x=-9 and 4 but dimensions can't be negative so x=4
So if the width is 4, then the length is 9 (4+5)
Hope this helps :)
Its an isosceles triangle
angle B = 47
and triangleADB is congruent to triangle ADC
from here we can say that BD = DC
now AD is a median and also altitude
so from here we can say angle x = 90
now in triangle ADB
90+47+y=180(ANGLE SUM PROPERTY )
y= 43
Plug in 0 for y to find the x intercept:
7x +3(0)= -21
7x=-21
x= -3
Plug in 0 for x to find y intercept:
7(0) + 3y= -21
3y= -21
y= -7