Answer:
The value of g(-2) and g(4) cannot be compared because they are two different functions with two completely different values.
Step-by-step explanation:
So, you plug in -2 in the function of the x in g(x) = 8x - 2
Then, you multiply 8 by -2 in g(-2) = 8x - 2
8 × -2 would be -16
Afterwards you subtract -16 by 2 in g(-2) = -16 - 2
The function of g(-2) is -14 in g (x) = -14
You plug in 4 in the function of x in g(4) = 8x - 2
g(4) = 8 (4) - 2
Then, You multiply 8 by 4 which will give you 32 in
g(4) = 32 - 2
Lastly, you subtract the 32 by 2 and the function of the answer would be 30 in g(x) = 30
Answer:
Step-by-step explanation:
logx
<=> logx + 2logy = a (1)
log
y=b <=> 3logx + 6logy =b (2)
(1),(2)=> logx= 
logy= 3a-b
=> log
=logy-logx=3a-b -( ) = 
log
= 
(logx+logy)=........ OK
[(21 + 6) - 32] : 9.2 = (27 - 32) : 9.2 = -5 : 9.2 = -46
