Step-by-step explanation:
A ball is launched straight up in the air from a height of 6 feet. The velocity as a function of time t is given by :
f(t) = -32 t+285
Height of the ball is :

C is constant. Here the ball is launched from a height of 6 feet. So,

At t = 2 s, 
At t = 9 s, 
Between 2 s and 9 s, the ball's height changed is : 1275 - 512 = 763 m.
Answer:
3/1 tsp. or 3 tsp.
Step-by-step explanation:
3/4 times 4
2) 5= 7 + -2
3) (-8) + 8 = 0
8) 3 + 5 = 8
9) 7 + 5 = 12
10) 4 = -8 + 4
The least number of buses needed to carry 710 passengers is 5.
Option A)5 is the correct answer.
<h3>What is the least number of buses needed to carry 710 passengers? </h3>
Given that;
- Number of passengers n = 710
- Least number of buses need B = ?
To get the least number of buses, we say;
Number of buses B = 710 ÷ 150
Number of buses B = 4.7 ≈ 5
The least number of buses needed to carry 710 passengers is 5.
Option A)5 is the correct answer.
Learn to solve more word problems here: brainly.com/question/2610134
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(√3n)-23=16
Put all of the numbers without a variable on the right side of the equation
(√3n)=39
Simplify
<span>1.732051n</span>=<span>39
</span>
Divide 39 by 1.732051
n=<span>22.516658
Round
n=22.5</span>