Can you give me a dividing problem that has a quotient of 3 and a remainder of 28

Which estimation could be used to make sure the answer is reasonable?

Naddika [18.5K]

Let's go through each answer.

A.

Answer: The amount left over was 4.05 L.

Estimation: 3.15 + 4.75 is about 7.

7 L – 4 L = 3 L

The amount left over was about 3 L.

This is incorrect because 3.15+4.75 is closer to 8 than 7.

B.

Answer: The amount left over was 3.95 L.

Estimation: 3.15 + 4.75 is about 8.

8 L – 4 L = 4 L

The amount left over was a little less than 4 L.

This is correct because 3.15+4.75 is close to 8 and to find the amount left over you do have to subtract.

The correct answer is B.

Answer: The amount left over was 3.95 L.

Estimation: 3.15 + 4.75 is about 8.

8 L – 4 L = 4 L

The amount left over was a little less than 4 L.

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3 0

3 years ago

Need help with courseReplace 250 with 575 and -3 with -5.

Svetlanka [38]

Given

The demand function

$p(x)=\frac{250}{\sqrt{x}}-5$

To determine:

a) The revenue function.

b) The marginal revenue.

c) The marginal revenue when x=200.

d) The equation of tangent, and its derivation.

Explanation:

It is given that,

$p(x)=\frac{250}{\sqrt{x}}-5$

a) The revenue function is given by,

$\begin{gathered} R(x)=x\cdot p(x) \\ R(x)=x\times(\frac{250}{\sqrt{x}}-5) \\ R(x)=250\sqrt{x}-5x \end{gathered}$

b) The marginal revenue function is,

$\begin{gathered} R^{\prime}(x)=\frac{d}{dx}(R(x)) \\ =\frac{d}{dx}(250\sqrt{x}-5x) \\ =250\times(\frac{1}{2}\times x^{-\frac{1}{2}})-5 \\ =\frac{125}{\sqrt{x}}-5 \end{gathered}$

c) The marginal revenue when x=200 is,

$\begin{gathered} R^{\prime}(200)=\frac{125}{\sqrt{200}}-5 \\ =\frac{125}{10\sqrt{2}}-5 \\ =8.8388-5 \\ =3.8388 \\ =3.84 \end{gathered}$

Hence, the marginal revenue is 3.84.

d) Let y=mx+c is the tangent.

Then,

$y=3.84x+c$

That implies, for y=12.68, and x=200,

$\begin{gathered} 12.68=3.84\times200+c \\ 12.68=768+c \\ c=12.68-768 \\ c=-755.32 \end{gathered}$

Hence, the equation of tangent is,

$y=3.84x-755.32$

8 0

11 months ago

Given the function f(x)=x^2-8x+13f(x)=x, determine the average rate of change of the function over the interval −1≤x≤6.

Ann [662]

Given:

Consider the given function is:

$f(x)=x^2-8x+13$

To find:

The average rate of change of the function over the interval $-1\leq x\leq 6$ .

Solution:

The average rate of change of the function f(x) over the interval [a,b] is:

$m=\dfrac{f(x_2)-f(x_1)}{x_2-x_1}$

We have,

$f(x)=x^2-8x+13$

At $x=-1$ ,

$f(-1)=(-1)^2-8(-1)+13$

$f(-1)=1+8+13$

$f(-1)=22$

At $x=6$ ,

$f(6)=(6)^2-8(6)+13$

$f(6)=36-48+13$

$f(6)=1$

Now, the average rate of change of the function f(x) over the interval $-1\leq x\leq 6$ is:

$m=\dfrac{f(6)-f(-1)}{6-(-1)}$

$m=\dfrac{1-22}{7}$

$m=\dfrac{-21}{7}$

$m=-3$

Therefore, the average rate of change of the function f(x) over the interval $-1\leq x\leq 6$ is -3.

6 0

2 years ago

Graph the equation y=-x. is (5,5) on the line? what is the slope of the line?

bezimeni [28]

You'll actually need to graph for the first segment
but the second part can be solved with algebra

The equation of the line is y(x)=-x

if we test the co0ordinates we can find if the point lies on the line

(5,5)
y(x)=-x

Using the x co-ordinate
y(5)= -5
y=-5

Leaving us with (5,-5)

Because (5,-5) is not (5,5)
This is not a point on the line

The slope of the line is -1

4 0

3 years ago

Which table represents y as a function of x

iren2701 [21]

Answer:

where are the tables i need a photo?

Step-by-step explanation:

6 0

2 years ago