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Lostsunrise [7]
3 years ago
7

What is the answer to 0.55 divided by 100

Mathematics
2 answers:
ratelena [41]3 years ago
7 0
The answer is 0.0055
DENIUS [597]3 years ago
5 0
Move the decimal over 2 spaces which would make it <span>.0055</span>
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The volume of a soap bubble is 555.4 mm^2 Find the radius and diameter of the soap bubble. Use 3.14 for pi
SashulF [63]

Answer:

radius=11.5

diameter=23

Step-by-step explanation:

The volume of a sphere is V=4/3 Pi r^3

We can use this to solve for the radius.

555.4= 4/3 (3.14)r^3

Solve for r how you would any other equation. Multiply 4/3 and 3.14.

555.4=4.187 r^3

Divide both sides by 4.187

132.65=r^3

To get rid of the ^3, find the cube root of both sides on a calcualtor.

r= 11.5

The diameter is the radius time two.

11.5 (2)=23.

Hope this helps!

Note: When I say both sides, I mean both sides of the = sign.

4 0
3 years ago
8.52 The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches
sweet [91]

Answer:

Heights of 29.5 and below could be a problem.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches.

This means that \mu = 32, \sigma = 1.5

There may be a problem when a child is in the top or bottom 5% of heights. Determine the heights of 2-year-old children that could be a problem.

Heights at the 5th percentile and below. The 5th percentile is X when Z has a p-value of 0.05, so X when Z = -1.645. Thus

Z = \frac{X - \mu}{\sigma}

-1.645 = \frac{X - 32}{1.5}

X - 32 = -1.645*1.5

X = 29.5

Heights of 29.5 and below could be a problem.

4 0
3 years ago
Solve for x^2-2x+1=0
seraphim [82]

Answer:

x=1

Step-by-step explanation:

x^2-2x+1=0\\

We will start by using the quadratic formula.

\frac{-(-2)+-\sqrt{(-2)^2-4(1)(1)}}{2(1)}

We will simplify that and get:

\frac{-(-2)}{2(1)}

So our answers would be:

x=1

7 0
3 years ago
Solve 2(4x + 5) &gt; 7x + 20.
choli [55]
2(4x+5)>7x+20  perform indicated multiplication on left side

8x+10>7x+20  subtract 7x from both sides

x+10>20  subtract 10 from both sides

x>10

or in interval notation, x=(10, +oo)
8 0
4 years ago
0.2x+2.7x−8.1=6.9+1.1x<br> plz help<br> 25 points on the line
ololo11 [35]

Answer:

Step-by-step explanation:

0.2x + 2.7x - 8.1 = 6.9 + 1.1x

0.2x + 2.7x - 1.1x = 6.9 + 8.1

1.8x = 15

x = 15/1.8

x = 8.33

6 0
3 years ago
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