Answer:
y = 2
Step-by-step explanation:
Given
![\sqrt[3]{3y+2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3y%2B2%7D)
+ 4 = 6 ( subtract 4 from both sides )
= 2 ( cube both sides )
3y + 2 = 2³ = 8 ( subtract 2 from both sides )
3y = 6 ( divide both sides by 3 )
y = 2
Answer:
A-3, B-4, C-1, D-2
Step-by-step explanation:
A:
- 5x-(3x+1)
- Expand, 5x-3x-1
- Combine like terms, 2x-1
B:
- 5x-(-3x-1)
- Expand, 5x+3x+1
- Combine like terms, 8x+1
C:
- -5x-(3x+1)
- Expand, -5x-3x-1
- Combine like terms, -8x-1
D:
- -5x-(-3x-1)
- Expand, -5x+3x+1
- Combine like terms, -2x+1
Answer:
3rd choice
Step-by-step explanation:
(7y^6)(2y^-4)^2
= (7y^6)(4y^-8)
Calculate:
(7y^6) * (4y^-8)
28y^-2
Express with a positive exponent:
28 * 1/y^2
Gives an output of 1 I think
