Ask question

Ask question

All categories

Anestetic [448]

3 years ago

15

For each store what is the ratio of the number of cans to the price? Super saver 12 pack 4 for $10, shop smart 24 pack 2 for $9,

price busters 12 packs 3 for $9

1 answer:

expeople1 [14]3 years ago

4 0

At Super Saver, 4 packs costs $10, so 12 × 4 = 48 gets us the amount if cans, which we can use to calculate the ratio. The ratio will be 48 cans : $10, or 4.8 cans : $1. Shop Smart will use the same principle, 24 × 2 = 48, so 48 cans : $9, or 5 1/3 cans : $1. And at Price Busters, 12 × 3 = 36 cans : $9, or 3 cans for $1. Overall, Shop Smart has the best value per can, next coming with Super Saver, then Price Busters.

You might be interested in

Solve........3 (5p - 3) = 5 (p - 1)

romanna [79]

Step 1: multiply the numbers in front of the parentheses with each term inside the parentheses

15p - 9 = 5p - 5

Step 2: get like terms on the same side

10p = 4

Step 3: divide both sides by 10

p = 4/10

Step 4: simplify

p = 2/5

7 0

3 years ago

How do you reduce ln(3^-e e^3) to simplest form

leva [86]

The logarithm of a product is equal to the sum of logarithms:

$\ln(3^{-e}e^3)=\ln3^{-e}+\ln e^3$

Drop the exponents:

$-e\ln3+3\ln e$

The logarithm of a number is equal to 1 if the base of the logarithm is the same as the number itself:

$-e\ln3+3$

7 0

3 years ago

Try this hard Math Problem if you dare!!

Dennis_Churaev [7]

Answer:

a. $(x - 3)^2 + 16$

b. $8(x -7)^2$

c. $(a^2 - 1)(7x - 6)$ or $(a+1)(a-1)(7x-6)$

d. $(x^2-4)(x^2+3)$ or $(x-2)(x+2)(x^2+3)$

e. $(a^n+b^n)(a^n-b^n)(a^{2n} +b^{2n})$

Step-by-step explanation:

$a.\ (x + 1)^2 - 8(x - 1) + 16$

Expand

$(x + 1)(x + 1) - 8(x - 1) + 16$

Open brackets

$x^2 + x + x + 1 - 8x + 8 + 16$

$x^2 + 2x + 1 - 8x + 24$

Collect Like Terms

$x^2 + 2x - 8x+ 1 + 24$

$x^2 - 6x+ 25$

Express 25 as 9 + 16

$x^2 - 6x+ 9 + 16$

Factorize:

$x^2 - 3x - 3x + 9 + 16$

$x(x -3)-3(x - 3) + 16$

$(x - 3)(x - 3) + 16$

$(x - 3)^2 + 16$

$b.\ 8(x - 3)^2 - 64(x-3) + 128$

Expand

$8(x - 3)(x - 3) - 64(x-3) + 128$

$8(x^2 - 6x+ 9) - 64(x-3) + 128$

Open Brackets

$8x^2 - 48x+ 72 - 64x+192 + 128$

Collect Like Terms

$8x^2 - 48x - 64x+192 + 128+ 72$

$8x^2 -112x+392$

Factorize

$8(x^2 -14x+49)$

Expand the expression in bracket

$8(x^2 -7x-7x+49)$

Factorize:

$8(x(x -7)-7(x-7))$

$8((x -7)(x-7))$

$8(x -7)^2$

$c.\ 7a^2x - 6a^2 - 7x + 6$

Factorize

$a^2(7x - 6) -1( 7x - 6)$

$(a^2 - 1)(7x - 6)$

The answer can be in this form of further expanded as follows:

$(a^2 - 1^2)(7x - 6)$

Apply difference of two squares

$(a+1)(a-1)(7x-6)$

$d.\ x^4 - x^2 - 12$

Express $x^4$ as $x^2$

$(x^2)^2 - x^2 - 12$

Expand

$(x^2)^2 +3x^2- 4x^2 - 12$

$x^2(x^2+3) -4(x^2+3)$

$(x^2-4)(x^2+3)$

The answer can be in this form of further expanded as follows:

$(x^2-2^2)(x^2+3)$

Apply difference of two squares

$(x-2)(x+2)(x^2+3)$

$e.\ a^{4n} -b^{4n}$

Represent as squares

$(a^{2n})^2 -(b^{2n})^2$

Apply difference of two squares

$(a^{2n} -b^{2n})(a^{2n} +b^{2n})$

Represent as squares

$((a^{n})^2 -(b^{n})^2)(a^{2n} +b^{2n})$

Apply difference of two squares

$(a^n+b^n)(a^n-b^n)(a^{2n} +b^{2n})$

6 0

3 years ago

suter [353]

That sounds horrible

6 0

2 years ago

Given the following students' test scores (95, 92, 90, 90, 83, 83, 83, 74, 60, and 50), identify the mean, median, mode, range,

il63 [147K]

Mean- 71.7
median- 83
mode- 90, 83
range- 45
variance- 50

i do not remember standard deviation.

3 0

3 years ago