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irakobra [83]
3 years ago
14

Factor f(x)=x2−8x+16 (A) (x−4)2 (B) (x+8)2 (C) (x−8)2 (D) (x+4)2

Mathematics
1 answer:
Fynjy0 [20]3 years ago
3 0

Answer:

A

Step-by-step explanation:

(x-4)^2 = x^2 -4x -4x + (-4)*(-4)

= x^2-8x+16 as required

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If a simple harmonic motion is described by x = 3 cos(πt), starting from t = 0 s, what is the first occurrence of a value of t f
poizon [28]

Answer:

The first occurence of t for which x = 0 is t = 0.5.

Step-by-step explanation:

The harmonic motion is described by the following equation.

x(t) = 3\cos{\pi t}

What is the first occurrence of a value of t for which x = 0?

This is t when x(t) = 0. So

x(t) = 3\cos{\pi t}

3\cos{\pi t} = 0

\cos{\pi t} = \frac{0}{3}

\cos{\pi t} = 0

The inverse of the cosine is the arcosine. So we apply the arcosine function to both sides of the equality.

\arccos{\cos{\pi t}} = \arccos{0}

\pi t = \frac{\pi}{2}

t = \frac{\pi}{2 \pi}

t = \frac{1}{2}

t = 0.5

The first occurence of t for which x = 0 is t = 0.5.

3 0
3 years ago
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