I think it’s a reciprocal function
Here the graph y=x²
Taking the 1st derivative here of the y it will be
y1 = 2x
m=-1/3
That is m=2x
so x=-1/6
so y=(-1/6)²=1/36
So the coordinate of point will be=(-1/6 , 1/36)
The third side can be represented by D) 
Step-by-step explanation:
Step 1:
According to the Pythagorean theorem, the square of the hypotenuse will be equal to the sum of the squares of the other two sides.
In the given triangle, the hypotenuse is the side that is represented by z. Another side on the triangle is represented by the value y.
Step 2:
Assume the other side of the triangle measures x units.
So according to the Pythagorean theorem,

which is option D.
Answer:
a
Step-by-step explanation:
Answer:
![\large\boxed{\ln\sqrt[3]{e^4}=\dfrac{4}{3}}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B%5Cln%5Csqrt%5B3%5D%7Be%5E4%7D%3D%5Cdfrac%7B4%7D%7B3%7D%7D)
Step-by-step explanation:
![\text{Use}\\\\\sqrt[n]{a^m}=a^\frac{m}{n}\\\\\ln a^n=n\ln a\\\\\ln e=1\\-----------\\\\\ln\sqrt[3]{e^4}=\ln e^\frac{4}{3}=\dfrac{4}{3}\ln e=\dfrac{4}{3}\cdot1=\dfrac{4}{3}](https://tex.z-dn.net/?f=%5Ctext%7BUse%7D%5C%5C%5C%5C%5Csqrt%5Bn%5D%7Ba%5Em%7D%3Da%5E%5Cfrac%7Bm%7D%7Bn%7D%5C%5C%5C%5C%5Cln%20a%5En%3Dn%5Cln%20a%5C%5C%5C%5C%5Cln%20e%3D1%5C%5C-----------%5C%5C%5C%5C%5Cln%5Csqrt%5B3%5D%7Be%5E4%7D%3D%5Cln%20e%5E%5Cfrac%7B4%7D%7B3%7D%3D%5Cdfrac%7B4%7D%7B3%7D%5Cln%20e%3D%5Cdfrac%7B4%7D%7B3%7D%5Ccdot1%3D%5Cdfrac%7B4%7D%7B3%7D)